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allsm [11]
3 years ago
8

What element has the electron configuration 1s22s22p63s23p64s23d104p65s24d105p66s24f145d106p2?

Chemistry
2 answers:
Sergeu [11.5K]3 years ago
6 0

Answer:

Lead, Pb

Explanation:

Electron configuration of an element depicts the arrangement or the distribution of electrons in different energy levels (orbitals) within the atom. This arrangement is based on the Aufbau principle which states that the electrons are added such the orbital with the lowest energy gets filled up first.

The given electron configuration is:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p²

The total number of electrons = 82

For a neutral atom; number of electrons = atomic number(Z)

Based on the periodic table, the element with atomic number = 82 is lead (Pb).

Marina CMI [18]3 years ago
3 0
<span>6s²4f¹⁴5d¹⁰6p²
6 shows that the element is in the 6 period,
6p² shows that the element is in the 14th group. (1 and 2 groups have s -electrons as last ones, 13 group has s²p¹, and 14 group has s²p²)
The element is Pb.

</span>
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Heat of reaction (i.e enthalpy of reaction) is the quantity of heat that is required to be added or removed when a chemical reaction is taken place in order to maintain all of the compounds present at the same temperature.

The formula used to calculate the heat of the reaction can be expressed as follows:

Q = mcΔT

where:

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From the information given:

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∴

The change in temperature i.e. ΔT = T₂ - T₁

ΔT = 91.5° C - 25° C

ΔT = 66.5° C

The number of moles of CuSO₄ = 1.00 mol/dm³ × 50.0 cm³

\mathbf{= (1 \times \dfrac{50}{1000})\ moles}

= 0.05 moles

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Then;

Using the relation:

\mathbf{number \ of \ moles = \dfrac{mass}{molar \ mass}}}

By crossing multiplying;

mass of CuSO₄ = number of moles of CuSO₄ ×  molar mass of CuSO₄

mass of CuSO₄ = 0.05 moles  × 159.609 g/moles

mass of CuSO₄ = 7.9805 grams

∴

Using the formula from above:

Q = mcΔT

Q = 7.9805 g × 4.18 kJ/g °C × 66.5° C

Q = 2218.34 kJ

Therefore, we can conclude that the heat of the reaction is 2218.34 kJ

Learn more about the chemical reaction here:

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Answer:

False

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