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allsm [11]
3 years ago
8

What element has the electron configuration 1s22s22p63s23p64s23d104p65s24d105p66s24f145d106p2?

Chemistry
2 answers:
Sergeu [11.5K]3 years ago
6 0

Answer:

Lead, Pb

Explanation:

Electron configuration of an element depicts the arrangement or the distribution of electrons in different energy levels (orbitals) within the atom. This arrangement is based on the Aufbau principle which states that the electrons are added such the orbital with the lowest energy gets filled up first.

The given electron configuration is:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p²

The total number of electrons = 82

For a neutral atom; number of electrons = atomic number(Z)

Based on the periodic table, the element with atomic number = 82 is lead (Pb).

Marina CMI [18]3 years ago
3 0
<span>6s²4f¹⁴5d¹⁰6p²
6 shows that the element is in the 6 period,
6p² shows that the element is in the 14th group. (1 and 2 groups have s -electrons as last ones, 13 group has s²p¹, and 14 group has s²p²)
The element is Pb.

</span>
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What volume of nitrogen (n2) would be completely consumed in the reaction with 30.80 g of
Shtirlitz [24]

The answer is 285.33g nitrogen would be completely consumed in the reaction with 30.80 g of hydrogen gas.

<h3>What is a mole ?</h3>

A mole is defined as 6.02214076 × 10²³ atoms, molecules, ions, or other chemical units.

Write a balanced equation.

Calculate the moles of H₂ in 30.8 g.

Calculate the moles of N₂ required to react with H₂.

Calculate the mass of N₂.

Calculate the initial mass of N₂.

Start with a balanced equation.

N₂ + 3H₂ --> 2NH₃

Calculate the moles of H₂ in 30.8 g.

n = m/M; where n = moles, m = mass, and M = molar mass.

M(H₂) = 1.008 g/mol

n(H₂) = (30.8 g)/(1.008 g/mol) = 30.56 mol H₂

Calculate the moles of N₂ required to react with 30.56 mol H₂ , using the mole ratio between H₂ and N₂ in the balanced equation.

30.56 mol H₂ × 1 mol N₂/3 mol H₂ = 10.18 mol N₂

Calculate the mass of N₂ in 10.18 mol.

m = n × M

M(N₂) = 2 × 14.007 g/mol N = 28.014 g/mol N₂

m(N₂) = 10.18 mol × 28.014 g/mol = 285.33g N₂

Therefore 285.33g nitrogen would be completely consumed in the reaction with 30.80 g of hydrogen gas.

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5 0
2 years ago
Be sure to answer all parts.
Natali5045456 [20]

Answer:

38.7%

41.3%

20%

Explanation:

The percentage composition helps to know the what percent of the total mass of a compound is made up of each of the constituent elements or groups.

To solve this problem:

  • find the formula mass by adding the atomic masses of the atoms that makes up the compound.
  • place the mass contribution of the element or group to the formula mas and multiply by 100;

Compound:

 Ca₃(PO₄)₂

  Formula mass = 3(40) + 2[31 + 4(16)]

                           = 120 + 2(95)

                           = 120 + 190

                           = 310

%C = \frac{3(40)}{310} x 100  = 38.7%

%P = \frac{8(16)}{310} x 100  = 41.3%

%O = \frac{2(31)}{310} x 200  = 20%

8 0
3 years ago
An invasive species is a species that disrupts the ecosystem into which it is introduced by displacing species.
sveta [45]

Invasive species can do all sorts of damage to an existing ecosystem, including changing habitats and starving native animals of food and resources.

<h3>What is an invasive species?</h3>

An invasive species is an organism that causes ecological or economic harm in a new environment where it is not native.

Invasive species can change the food web in an ecosystem by destroying or replacing native food sources. The invasive species may provide little to no food value for wildlife. Invasive species can also alter the abundance or diversity of species that are important habitats for native wildlife.

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7 0
2 years ago
A sample contains 0.500 mol of aluminum. What is the mass of aluminum in the sample (in grams)?
postnew [5]

Answer:

\boxed {\boxed {\sf About \ 13.5 \ grams \ of \ Al}}

Explanation:

To convert from moles to grams we must use the molar mass, which can be found on the Periodic Table.

  • Aluminum (Al): 26.981538 g/mol

Use this number as a fraction.

\frac{26.981538 \ g \ Al }{1 \ mol \ Al}

Multiply by the given number of moles.

0.500 \ mol \ Al *\frac{26.981538 \ g \ Al }{1 \ mol \ Al}

The moles of aluminum will cancel.

0.500 *\frac{26.981538 \ g \ Al }{1 }

0.500 *26.981538 \ g \ Al

13.490769 \ g  \ Al

The original number of moles, 0.500, has 3 significant figures, so our answer must have the same.

For the number we calculated, that is the tenth place. The 9 in the hundredth place tells us to round the 4 to a 5.

13.5 \ g \ Al

There are about <u>13.5 grams of aluminum</u> in 0.500 moles.

5 0
3 years ago
Read 2 more answers
Zippy decides he needs a drink to wash down the cold Pring Pongs. There are two 355 mL cans of Kookie Cola in the mini-bar.
Lady bird [3.3K]

20.7 Degree celsius is the temperature of Zippy's room.

Explanation:

The initial conditions of the kookie cola will be depicted by P1,V1 and T1.

P1= 36.5 psi or 2.4816 atm

V1= 355ml or 0.35 L

T1= 275.5K

The final conditions are given P2,V2 and T2

P2= 38.9 psi or 2.6469 atm

V2 = 355 ml or 0.35 L

also the solubility of the carbon dioxide does not change with temperature.

Applying the formula

P1VI/T1=P2V2/T2

since volume does not change and remains constant.

It can be written as:

P1/T1=P2/T2

= 2.4816/275.5=2.6469/T2

T2= 293.85 K

7 0
3 years ago
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