The given question is incomplete. The complete question is as follows.
The solubility product of calcium fluoride () is at 25 degrees C. Will a fluoride concentration of 1.0 mg/L be soluble in a water containing 200 mg/L of calcium?
Explanation:
Reaction equation for the given chemical reaction is as follows.
Therefore, expression for will be as follows.
=
Also, moles of per liter = \frac{\text{mass of F^{-} per L}}{\text{molar mass of F}}[/tex]
=
=
Hence,
=
= M
Now, moles of per L = \frac{\text{mass of Ca^{2+} per L}}{\text{molar mass of Ca}}[/tex]
=
= M
Also,
=
= M
Hence, ionic product =
=
=
As, the ionic product is less than the , this means that the fluoride will be soluble in water containing the calcium.
Answer:
The correct answer would be C) Support
Answer:
1,1,1
decomposition reaction
Explanation:
The reaction equation is given as:
_Ca(OH)₂ → _CaO + _H₂O
This reaction is a decomposition reaction in which a single reactant breaks down to give two or more products.
To balance the equation, we assign variables a, b and c, then we use a mathematical approach to solve the problem;
aCa(OH)₂ → bCaO + cH₂O
Conserving Ca : a = b
O: 2a = b + c
H: 2a = 2c
let a = 1, b = 1 , c = 1