Answer:
1M
Explanation:
First, let us write a balanced equation for the reaction. This is illustrated below:
NaOH + HCl —> NaCl + H2O
From the equation above,
nA (mole of acid) = 1
nB (mole of the base) = 1
Data obtained from the question include:
Vb (volume of base) = 50mL
Mb (Molarity of base) = 0.2M
Va (volume of acid) = 10mL
Ma (Molarity of acid) =?
Using MaVa/MbVb = nA/nB, we can calculate the molarity of the acid as follow:
Ma x 10/0.2 x 50 = 1
Cross multiply to express in linear form
Ma x 10 = 0.2 x 50
Divide both side by 10
Ma = (0.2 x 50)/10
Ma = 1M
The molarity of the acid is 1M
The mass of the blood is 5.8 kg.
<em>V</em> = 5.5 L = 5500 mL
Mass = 5500 mL × (1.06 g/1 mL) = 5800 g = 5.8 kg
Answer:
[C₆H₅NH₃⁺] = 0.0399 M
Explanation:
This excersise can be easily solved by the Henderson Hasselbach equation
C₆H₅NH₃Cl → C₆H₅NH₃⁺ + Cl⁻
pOH = pKb + log (salt/base)
As we have value of pH, we need to determine the pOH
14 - pH = pOH
pOH = 8.43 (14 - 5.57)
Now we replace data:
pOH = pKb + log ( C₆H₅NH₃⁺/ C₆H₅NH₂ )
8.43 = 9.13 + log ( C₆H₅NH₃⁺ / 0.2 )
-0.7 = log ( C₆H₅NH₃⁺ / 0.2 )
10⁻⁰'⁷ = C₆H₅NH₃⁺ / 0.2
0.19952 = C₆H₅NH₃⁺ / 0.2
C₆H₅NH₃⁺ = 0.19952 . 0.2 = 0.0399 M
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