The velocity, expressed in terms of ME, RE is given as .
The maximum height that the rocket could reach if launched vertically is H = (¹/₂v₀²)/g.
<h3>Maximum height of the rocket</h3>The maximum height reached by the rocket can be modeled using conservation of energy as shown below;
P.Ei + K.Ei = K.Ef + P.Ef
P.E = K.E
mgH = ¹/₂mv²
H = (¹/₂v₀²)/g
Learn more about conservation of energy here: brainly.com/question/166559
Answer:
25 m/s
Explanation:
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here is the complete question:
'Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 7.0m/s . Once free of this area, it speeds up to 12m/s in 8.0 s. At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed. What is the final Speed?'
SOLUTION
initial speed (u) = 7 m/s
final speed (v) = 13 m/s
initial acceleration time (t1) = 8 s
final acceleration time (t2) = 16 s
what is the higher cruising speed?
acceleration =
acceleration = = 0.75 m/s^{2}
since the train accelerates at the same rate, the increase in speed will be = acceleration x time (t2)
= 0.75 x 16 = 12 m/s
therefore the higher cruising speed = increase in speed + initial speed
= 12 + 13 = 25 m/s