Answer: 43 degrees
Explanation:
The force of the crutch can be broken into components. The horizontal component of F is the static friction force keeping the crutch from sliding. The vertical component is opposing the weight and is the Normal force. Using the orientation of the angle q, we have the following
fs = Fx = F sin (angle (tita))
N = Fy = F cos (angle(tita))
Maximum angle implies maximum static friction
Therefore,
fsmax = UsN = Us x F cos(angle tita)
Where U = miyu
F sin(angle tita) = Us x Fcos (angle tita)
Sin (angle tita) / cos (angle tita) = Us
Therefore, tan (angle tita) = Us
Angle tita = tan^-1(Us) = tan^-1 (0.931) = 42.95 degrees = 43 degrees
There for Angle tita Max = 43 degrees
Answer:
curves downward, below the initial velocity vector.
Explanation:
Projectile launches are generally divided into two types: the oblique throw and the free fall. The free fall of bodies consists of throwing or abandoning projectiles from a hill or any unevenness that has a height in relation to a frame (usually the ground), while the oblique launch consists of launching a projectile at an angle. any relative to a frame (usually the ground).
Regardless of the type, when reading the paragraph above, we can say that the trajectory of a projectile will always be curved down and below the initial velocity vector.
B = 0.018 T Ans,
Since, it is moving in a circular path, thus, centripetal force will act on it i.e.
F =

where, m is the mass of the object, v is the velocity and r is the radius of circular path.
And, since a positive charge is moving, it will create magnetic force which is equal to F = qvB
where q is the charge, v is the velocity of the particle and B is the magnetic field.
Now, the two forces will be equal,
i.e.

= qvB
⇒

= qB
⇒B =

<span>putting the values, we get,
</span>
use q = 1.6 * 10^ -19
⇒ B = 0.018 T