Sawyer received two tubes of solution at 10 a.m., four tubes of solution at 12 p.m., eight tubes of solution at 3 p.m. and six t

Question

2 years ago

7

Sawyer received two tubes of solution at 10 a.m., four tubes of solution at 12 p.m., eight tubes of solution at 3 p.m. and six t

ubes of liquid at 6 p.m. Sawyer was told to divide the solution among five patients. How many tubes of solution did each patient get? Explain your process in the space below.

Physics

1 answer:

Reptile [31] · Answer 1 · 2023-02-24T09:47:56+03:00

Using the division operation, the number of tubes gotten by each patient can be obtained by dividing 20 by 5. Hence, each patient will get 4 tubes of solution.

Tubes of solution received :

10 a.m = 2 tubes
12 p.m = 4 tubes
3 p.m = 8 tubes
6 p.m = 6 tubes

Total tubes received :

(2 tubes + 4 tubes + 8 tubes + 6 tubes) = 20 tubes

Number of patients = 5 patients

Number of tubes of solution gotten by each patient :

(Total tubes of solution ÷ number of patients)

Tubes of solution per patient = (20 ÷ 5) = 4 tubes

Therefore, each patient will get 4 tubes of solution.

Learn more : brainly.com/question/25339242