A 1-kilogram ball has a kinetic energy of 50 joules the speed of the ball is

A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away

Tatiana [17]

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

<h3>What is the electric field intensity 20cm away from the rod along its perpendicular bisector?</h3>

Generally, the equation for the initial electric field intensity is mathematically given as

$dEp=\int{kd/r}cosd\theta$

Therefore

$e1=kd/r{sin\theta2+sinR1}$

Hence

$E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2$

E1=B*9*10^{13})/(10*110)* $\sqrt{2}$

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m

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6 0

2 years ago

When a 1.0-kilogram cart moving with a speed of 0.50 meter per second on a horizontal surface collides with a second 1.0-kilogra

yanalaym [24]

The speed of the combined carts after the collision is 0.25 m/s

Explanation:

We can solve this problem by using the principle of conservation of momentum. In fact, the total momentum of the system must be conserved before and after the collision, so we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 1.0 kg$ is the mass of the first cart

$u_1 = 0.50 m/s$ is the initial velocity of the first cart

$m_2 = 1.0 kg$ is the mass of the second cart

$u_2 = 0$ is the initial velocity of the second cart

$v$ is the final combined velocity of the two carts

Re-arranging the equation and substituting the values, we find: the final velocity:

$v=\frac{m_1 u_1}{m_1+m_2}=\frac{(1.0)(0.50)}{1.0+1.0}=0.25 m/s$

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4 0

4 years ago

ANSWER IN LESS THAN A MIN!! EASY!!

snow_lady [41]

Answer:

I think they are both equal in strength but make sure from others

7 0

3 years ago

Read 2 more answers

A 9 × 1014 Hz laser emits a 8.8 μs pulse, 5.0 mm in diameter, with a beam energy density of 0.8 J/m3. The number of wavelengths

julsineya [31]

To solve this problem we will apply the concepts related to Frequency (Reverse to Period) and the description of the wavelength as a function of the speed of light at the rate of frequency.

Our Laser frequency is given as

$f = 9*10^{14}Hz$

Therefore the laser wavelength would be

$\lambda = \frac{c}{f}$

Where,

c = Speed of light

f = Frequency

$\lambda = \frac{3*10^8}{ 9*10^{14}}$

$\lambda = 3.33*10^{-7}$

The laser pulse is emitted at a period (T) of $8.8*10^{-6}s$

Therefore the pulse wavelength would be

$\lambda' = \frac{c}{f}$

$\lambda' = c \frac{1}{f} \rightarrow \frac{1}{f} = T$

$\lambda' = c *T$

$\lambda' = (3*10^8)(8.8*10^{-6})$

$\lambda' = 2640m$

Finally the number of wavelengths is the ratio between the two wavelengths, then

$n = \frac{\lambda'}{\lambda}$

$n = \frac{2640}{3.33*10^{-7} }$

$n = 7.927*10^9$

The number of wavelengths in the beam length is closer to $7.927*10^9$

8 0

3 years ago

Newton's law of universal gravitation, the law of conservation of mass, the law of superposition, and the laws of thermodynamics

Llana [10]

Answer:

D

Explanation:

There are no exceptions to these laws under specific stated conditions..

The laws of science are statements that describe or predict a range of phenomena as they appear in nature. Laws explain facts determined by experiment. Laws do not have absolute certainty and be changed by future experiments and observations.

5 0

3 years ago