Question

At what place should the object be kept to form its erect and magnified image in case of a concave mirror?

Answer 1

Answer:

Object should be placed between P and F so that the image is virtual, erect and magnified!

Explanation:

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Answer 2

Answer:

The answer will be B

Explanation:

When the image is erect and magnified it means that the magnification is positive and greater than  1.  

The mirror formula is  1u+1v=1f,  where,

u  is the distance of the object from the mirror,

v  is the distance of the image from the mirror, and,

f  is the focal length of the mirror.

⇒1v=1f−1u=u−fuf.  

⇒v=ufu−f.  

The magnification,  M=−vu.  

⇒M=−fu−f=ff−u  

Also, the magnification is  M=height of the imageheight of the object.  

As per the sign convention, in a concave mirror,  u,v  and  f  are all negative, the height or an erect image is positive and the height of an inverted image is negative.

Hence, for an erect image, it is necessary to have  M>0.  

⇒M=ff−u>0.  

⇒f−u<0  since  f<0.  

⇒f<u.  

⇒|u|<|f|  since  f<0.  

⇒  The distance of the object from the mirror is lesser than the focal length.

Further,  |f|>|f−u|  since both  f  and  u  both have the same sign.

⇒ff−u>1.  

⇒  The image is magnified i.e. the height of the image is greater than the height of the object.