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DanielleElmas [232]
3 years ago
5

Is it possible to get more work out of a machine then you put in yes or no?

Physics
1 answer:
stellarik [79]3 years ago
7 0
All machines make work easier, but they don't increase the amount of work that is done. You can never get more work out of a machine than you put into it. In fact, a machine always does less work on an object than the user does on the machine. ... All machines involve motion, so they all have friction.
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What factors determine the magnitude of the electric force between two particles ?
sattari [20]

Answer:

Force between two particles depends on the magnitude of charge on the particles and distance between them

Explanation:

We know that

According to coulomb's law electric force between two Particles is given by

F=\frac{1}{4\pi \epsilon _0}\frac{Q_1Q_2}{R^2}=\frac{KQ_1Q_2}{R^2}, here K is constant Q_1\ and\ Q_2\ charge\ on\ the\ particles

R is the distance between the charge particles

So force between two particles depends on the magnitude of charge on the particles and distance between them

6 0
3 years ago
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Which material(s) listed below is an example of a persistent organic pollutant?
grigory [225]

Answer:

mercury

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Explanation:

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4 0
2 years ago
A 140 g baseball is moving horizontally to the right at 35 mis when it is hit by the bat. the ball fl ies off to the le ft at 55
Anit [1.1K]

Answer:

J = 12.32kg*m/s

Explanation:

Assumptions: I'm assuming mis is m/s

Given: The baseball's mass is 140g, so convert to kg, 0.140kg. (Good rule of thumb, in physics convert grams to kilograms). It is initially traveling 35 m/s to the right.

When it hits the bat, it flies left with a velocity of 55 m/s at an angle of 25°. To reiterate:

mass = 0.140kg, Initial: 35m/s, Final: 55m/s at an angle of 25°

For this problem, we have to use the impulse equation, but before that lets break the velocity into components (It will be apparent towards the end):

The initial velocity is moving only in the horizontal direction, so:

v_{0x} = 35 m/s

The final velocity has an x and a y component:

v_{fx} = 55cos(25) = 49.84692829m/s\\v_{fy} = 55sin(25) = 23.2440044m/s

Now the equation for impulse is (dp is Δp, which is difference in momentum; dv is Δv, the difference in velocity; J is impulse):

J = dp= m*dv

To get Δv, we have to find the difference of velocity, that is why we broke it into components. I'm going to define right as positive and left as negative. After that, we find the velocity vector:

dv_{x} = (35-(-49.84692829)) = 84.84692829 m/s\\dv_{y} = (0-(23.2440044)) = -23.2440044 m/s\\dv = \sqrt{(84.84692829)^2+(-23.2440044)^2} = 87.97320604m/s

Finally, substitute into the equation

J = m*dv\\J = 0.140kg * 87.97320604m/s\\J = 12.31624885kg*m/s\\J = 12.32 kg*m/s

J = 12.32kg*m/s

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3 years ago
The graph shows a heating curve for water. Between which points on the graph would condensation occur?
Effectus [21]

Answer:

Between R and S

Explanation:

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Is a tape dispenser a pulley or a wheel and axis? 
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It is a wheel and axis
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