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Annette [7]
4 years ago
10

Which value can be added to the set below without changing its mean?

Mathematics
2 answers:
Grace [21]4 years ago
6 0

Answer:

0 because it has no value.

Step-by-step explanation:

Tomtit [17]4 years ago
5 0

Answer:

15

Step-by-step explanation:

The mean of the first set is 15. If you add 15 to the set then it will equal 105. Then divide by 7 and then you get 15.

Hope this helps.

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What is the undefined variable in this equation (6x2 +3x) ÷ (3x) simplified 3x + 1
ozzi
X is the undefined variable hope it helps

4 0
3 years ago
Q and r are independent events. if p(q) = 1/4 and p(r)=1/5, find p(q and r)
klasskru [66]

Answer:

(b) \frac{7}{30}

Step-by-step explanation:

When two p and q events are independent then, by definition:

P (p and q) = P (p) * P (q)

Then, if q and r are independent events then:

P(q and r) = P(q)*P(r) = 1/4*1/5

P(q and r) = 1/20

P(q and r) = 0.05


In the question that is shown in the attached image, we have two separate urns. The amount of white balls that we take in the first urn does not affect the amount of white balls we could get in the second urn. This means that both events are independent.


In the first ballot box there are 9 balls, 3 white and 6 yellow.

Then the probability of obtaining a white ball from the first ballot box is:

P (W_{u_1}) = \frac{3}{9} = \frac{1}{3}

In the second ballot box there are 10 balls, 7 white and 3 yellow.

Then the probability of obtaining a white ball from the second ballot box is:

P (W_{u_2}) = \frac{7}{10}

We want to know the probability of obtaining a white ball in both urns. This is: P(W_{u_1} and W_{u_2})  

As the events are independent:

P(W_{u_1} and W_{u_2})  = P (W_{u_1}) * P (W_{u_2})

P(W_{u_1} and W_{u_2})  = \frac{1}{3}* \frac{7}{10}

P(W_{u_1} and W_{u_2})  = \frac{7}{30}

Finally the correct option is (b) \frac{7}{30}

3 0
3 years ago
Le<br> 8. Complete the syllogism.<br> If d=&gt; and e=&gt;f, then
Nikitich [7]
Then d = e by transitive property
8 0
3 years ago
3(s-4) &gt; 4s-12 i got s&gt;0 but im pretty sure thats incorrect so please help
Verizon [17]
Just gonna check your work...

3(s-4) > 4s -12
3s-12>4s-12
    +12      +12
3s>4s
-3s  -3s
0>s
s<0

So you are almost there, but the sign is in reverse.
6 0
4 years ago
How do I factor this polynomial? This one: z^2+8z+7?
MatroZZZ [7]

This is how I would factor it

8 0
3 years ago
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