All categories

3 years ago

Complete the scale by labeling the remaining tick marks

Mathematics

1 answer:

scoundrel [369]3 years ago

5 0

Answer:

Can you provide a picture?

I cannot help you if you don't.

You might be interested in

How to solve this equation by getting a value and b value

goblinko [34]

Answer:

a=±5

Step-by-step explanation:

25=5^2

Given that, x^2−10x+25=x^2−10x+5^2

Identity: a^2−2(ab)+b^2=(a-b)^2

Here, a=x and b=5

∴=(x−5)^2

Hope this helps

3 0

4 years ago

Let c be a positive number. A differential equation of the form dy/dt=ky^1+c where k is a positive constant, is called a doomsda

stich3 [128]

Answer:

The doomsday is 146 days

Step-by-step explanation:

Given

$\frac{dy}{dt} = ky^{1 +c}$

First, we calculate the solution that satisfies the initial solution

Multiply both sides by

$\frac{dt}{y^{1+c}}$

$\frac{dt}{y^{1+c}} * \frac{dy}{dt} = ky^{1 +c} * \frac{dt}{y^{1+c}}$

$\frac{dy}{y^{1+c}} = k\ dt$

Take integral of both sides

$\int \frac{dy}{y^{1+c}} = \int k\ dt$

$\int y^{-1-c}\ dy = \int k\ dt$

$\int y^{-1-c}\ dy = k\int\ dt$

Integrate

$\frac{y^{-1-c+1}}{-1-c+1} = kt+C$

$-\frac{y^{-c}}{c} = kt+C$

To find c; let t= 0

$-\frac{y_0^{-c}}{c} = k*0+C$

$-\frac{y_0^{-c}}{c} = C$

$C =-\frac{y_0^{-c}}{c}$

Substitute $C =-\frac{y_0^{-c}}{c}$ in $-\frac{y^{-c}}{c} = kt+C$

$-\frac{y^{-c}}{c} = kt-\frac{y_0^{-c}}{c}$

Multiply through by -c

$y^{-c} = -ckt+y_0^{-c}$

Take exponents of $-c^{-1$

$y^{-c*-c^{-1}} = [-ckt+y_0^{-c}]^{-c^{-1}$

$y = [-ckt+y_0^{-c}]^{-c^{-1}$

$y = [-ckt+y_0^{-c}]^{-\frac{1}{c}}$

i.e.

$y(t) = [-ckt+y_0^{-c}]^{-\frac{1}{c}}$

Next:

$t= 3$ i.e. 3 months

$y_0 = 2$ --- initial number of breeds

So, we have:

$y(3) = [-ck * 3+2^{-c}]^{-\frac{1}{c}}$

-----------------------------------------------------------------------------

We have the growth term to be: $ky^{1.01}$

This implies that:

$ky^{1.01} = ky^{1+c}$

By comparison:

$1.01 = 1 + c$

$c = 1.01 - 1 = 0.01$

$y(3) = 16$ --- 16 rabbits after 3 months:

-----------------------------------------------------------------------------

$y(3) = [-ck * 3+2^{-c}]^{-\frac{1}{c}}$

$16 = [-0.01 * 3 * k + 2^{-0.01}]^{\frac{-1}{0.01}}$

$16 = [-0.03 * k + 2^{-0.01}]^{-100}$

$16 = [-0.03 k + 0.9931]^{-100}$

Take -1/100th root of both sides

$16^{-1/100} = -0.03k + 0.9931$

$0.9727 = -0.03k + 0.9931$

$0.03k= - 0.9727 + 0.9931$

$0.03k= 0.0204$

$k= \frac{0.0204}{0.03}$

$k= 0.68$

Recall that:

$-\frac{y^{-c}}{c} = kt+C$

This implies that:

$\frac{y_0^{-c}}{c} = kT$

Make T the subject

$T = \frac{y_0^{-c}}{kc}$

Substitute: $k= 0.68$ , $c = 0.01$ and $y_0 = 2$

$T = \frac{2^{-0.01}}{0.68 * 0.01}$

$T = \frac{2^{-0.01}}{0.0068}$

$T = \frac{0.9931}{0.0068}$

$T = 146.04$

<em>The doomsday is 146 days</em>

4 0

3 years ago

Please help!! no files!!! i’ll mark you brainliest if you can explain your answer!!!!

Natasha2012 [34]

Answer:

a = 1.5

VW = 9 ft

Step-by-step explanation:

Since the tangent lines connect both circles, we know that the line VU and VX are congruent (equal). Thus, we can set them equal to each other and solve for a:

a + 4 = a² + 0.25 Set equal

a² - a = 3.75 Isolate a values

a² - a + 0.25 = 3.75 + 0.25 Complete the square

(a + 0.5)² = 4 Factor

a + 0.5 = 2 Simplify

a = 1.5

Now we need to calculate VW, but thats easy because its equal to TV, and since we know a, we can just plug it in:

((1.5) + 7.5) ft

9 ft

6 0

3 years ago

Help me with this question please, thank you !

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

[(27divided by (-3)-9] divided by [15-21}

=[-9-9] divided by 3

= 6divided by 3 = 2

<h2><u><em>if answer is correct so mark me as brain lest :-)</em></u></h2>

5 0

2 years ago

Jeremy has 50 ft of fencing to enclose a rectangular-pen for his dog. He plans on using a side of his house for one side of the

kotykmax [81]

The dimensions such as length is 18 and width is 16 or length is 32 and width is 9 will produce an enclosed area of 288ft.

<h3>What is the dimension of length and width?</h3>

We know that,

P = l + 2w

50 = l + 2w

50 - 2w = l

A = l x w

288 = (50 - 2w)w

288 = 50w -2w²

2w² - 50w + 288

By dividing throughout by 2

w² - 25w + 144

This is in quadratic equation form.

By applying quadratic formula,

w = (-(-25) ± $\sqrt{(-25)^{2}-4*1*144$ ) / 2

w = (-(-25) ± 7)/2

w1 = (-(-25) + 7)/2

w1 = (25 + 7) / 2

w1 = 16

w2 = (-(-25) - 7)/2

w2 = (25 - 7) / 2

w2 = 9

By substituting the values in eq1,

A = l x w

if w = 16

288 = l x 16

l = 288/16

l = 18

if w = 9

288 = l x 9

l = 288/9

l = 32

The dimensions will be length is 18 and width is 16 or length is 32 and width is 9.

To learn more about area of rectangle refer to :

brainly.com/question/25292087

#SPJ1

3 0

1 year ago

Complete the scale by labeling the remaining tick marks​

Complete the scale by labeling the remaining tick marks