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3 years ago

Solve log3(x+1)=log6(5-x) by graphing. what equations should be graphed

Mathematics

2 answers:

quester [9]3 years ago

6 0

Answer: a and d

Step-by-step explanation:

I got it right on edge

mixas84 [53]3 years ago

3 0

Answer:

x=1.25

Step-by-step explanation:

We want to solve $\log_3(x+1)=\log_6(5-x)$ by graphing.

We let $y=\log_3(x+1)$ and also

$y=\log_6(5-x)$ .

We graph both equations to obtain the graph shown in the attachment.

The two graphs intersect at (1.25,0.74)

Therefore the solution to $\log_3(x+1)=\log_6(5-x)$ is the x-coordinate of the point of intersection of the two graphs which is x=1.25.

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2 years ago

Read 2 more answers

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juin [17]

The correct answer is:

15 bicycles and 6 skateboards.

Explanation:

Let x represent the number of bicycles and y represent the number of skateboards. The first equation in our system is then

x+y = 21, since there are 21 total items in the shop.

Each bicycle has 2 tires and each skateboard has 4; this gives us the equation

2x+4y=54 (because they are ordering 54 tires).

This makes our system

$\left \{ {{x+y=21} \atop {2x+4y=54}} \right.$

We will use elimination to solve this; we first need one of the variables to have the same coefficient in both equations. We will make x the same, and we will do this by multiplying the first equation by 2:

$\left \{ {{2(x+y=21)} \atop {2x+4y=54}} \right. \\
\\\left \{ {{2x+2y=42} \atop {2x+4y=54}} \right.$

Now we will subtract the second equation from the first one:

$\left \{ {{2x+2y=42} \atop {-(2x+4y=54)}} \right. \\
\\-2y=-12$

Divide both sides by -2:

-2y/-2 = -12/-2

y = 6

There were 6 skateboards. Substituting this into the first equation,

x+6 = 21

Subtract 6 from each side:

x+6-6 = 21-6

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There were 15 bicycles.

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2 years ago

What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 12 - x2? (4 points)

wolverine [178]

Answer: 16 square units

Step-by-step explanation:

let the vertex in quadrant I be (x,y)

then the vertex in quadratnt II is (-x,y)

base of the rectangle = 2x

height of the rectangle = y

Area = xy

= x(12 - x²)

= -x³ + 12x

d(area)/dx = 3x² - 12 = 0 for a maximum of area

3x² = 12

x² = 4

x = ±2

y = 12-4 = 8

So, the largest area = 2 x 8 = 16 square units

7 0

2 years ago

Solve log3(x+1)=log6(5-x) by graphing. what equations should be graphed​

Solve log3(x+1)=log6(5-x) by graphing. what equations should be graphed