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insens350 [35]
3 years ago
14

Solve log3(x+1)=log6(5-x) by graphing. what equations should be graphed​

Mathematics
2 answers:
quester [9]3 years ago
6 0

Answer:  a and d

Step-by-step explanation:

I got it right on edge

mixas84 [53]3 years ago
3 0

Answer:

x=1.25

Step-by-step explanation:

We want to solve \log_3(x+1)=\log_6(5-x) by graphing.

We let  y=\log_3(x+1) and also

y=\log_6(5-x).

We graph both equations to obtain the graph shown in the attachment.

The two graphs intersect at (1.25,0.74)

Therefore the solution to \log_3(x+1)=\log_6(5-x)  is the x-coordinate of the point of intersection of the two graphs which is x=1.25.

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Rational numbers are numbers that can be expressed as a fraction (ratio). Irrational numbers can not be expressed like that (like sqrt(2)).

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If the result of adding them would be rational, then your irrational number can be expressed as the difference of two rational numbers, which itself is also a rational number. That cannot be, because it should be an irrational number. This contradiction forces that rational + irrational = irrational.

You can reason the same way for multiplication. Suppose rational * irrational = rational, you find that your irrational can be expressed as the fration of two rationals, which is a contradiction.
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