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insens350 [35]
3 years ago
14

Solve log3(x+1)=log6(5-x) by graphing. what equations should be graphed​

Mathematics
2 answers:
quester [9]3 years ago
6 0

Answer:  a and d

Step-by-step explanation:

I got it right on edge

mixas84 [53]3 years ago
3 0

Answer:

x=1.25

Step-by-step explanation:

We want to solve \log_3(x+1)=\log_6(5-x) by graphing.

We let  y=\log_3(x+1) and also

y=\log_6(5-x).

We graph both equations to obtain the graph shown in the attachment.

The two graphs intersect at (1.25,0.74)

Therefore the solution to \log_3(x+1)=\log_6(5-x)  is the x-coordinate of the point of intersection of the two graphs which is x=1.25.

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Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in. Find
mr Goodwill [35]

Answer:

The volume in such a package is 27648 in³

Step-by-step explanation:

Consider the provided information.

Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in.

Let the dimension are x by x by y.

Where x is the variable for the square base package and y is the variable for length.

Thus l=x, b=x and h=y

Then the volume of the box is: V(x)=x^2y (∵V=lbh)

The maximum combined length and girth is 144.

Therefore, 4x+y=144

y=144-4x

Substitute the value of y in volume of the box.

V(x)=x^2(144-4x)

V(x)=144x^2-4x^3

V'(x)=288x-12x^2

Substitute V'(x)=0.

0=288x-12x^2

12x(24-x)=0

x=0\ or\ x=24

Now apply second derivative test.

V''(x)=288-24x

V''(0)=288-24(0)>0 (Min)

V''(24)=288-24(24) (Max)

Hence, the maximum volume is at x=24

If x=24 then y=144-4(24)=48

Substituting value of x = 24 and y = 48 V(x)=x^2y gives 27648.

Hence, the volume in such a package is 27648 in³

5 0
3 years ago
PLEASE HELP
Gnesinka [82]

ANSWER

D

Step-by-step explanation:

d=√((x_2-x_1)²+(y_2-y_1)²)

3 0
3 years ago
Read 2 more answers
Which angles are complementary to
Molodets [167]
Complementary angles add up to 90°

∠BDC + ∠CDA = 90°

Answer: ∠BDC
8 0
3 years ago
A cone is placed inside a cylinder, as shown below. They have the same height and diameter. About how much space is inside the c
nadezda [96]

The space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.

<h3>What is a cone?</h3>

It is defined as the three-dimensional shape in which the base is a circular shape and if we go from circular base to top the diameter of the circle reduces and at the vertex, it becomes almost zero.

We know the volume of the cylinder is given:

\rm V = \pi r^2 h

r = 10/2 = 5 FT

h = 12 FT

\rm V = \pi (5)^2 \times 12

V = 300π cubic FT

Volume of the cone:

\rm v = \dfrac{\pi r^2 h}{3}

\rm v = \dfrac{\pi (5)^2 \times 12}{3}

v = 100π cubic FT

Space is inside the cylinder but outside the cone = 300π - 100π

= 200π cubic FT

= 628.32 cubic FT

Thus, the space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.

Learn more about the cone here:

brainly.com/question/16394302

#SPJ1

6 0
2 years ago
If a game consists of picking a number from a bag of beans numbered 2, 2, 3, 4, and 5 and flipping a coin, which probabilities a
White raven [17]

Answer:

I say C. Because 2 shows up twice for the bag of beans

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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