There is a major difference in between heating wire and fuse wire
Heating wire has a very high melting point so it can be heated to very high temperature and due to its nature it withstand the temperature and does not melt. They are made up of high melting substance like nichrome.
Fuse has a very low melting point so it cannot be heated to very high temperature and due to its nature it cannot withstand the temperature and get melted easily. When used it melts when the current exceeds a certain limit. That is why it is used a protective aid. Made up of Magnesium etc.
So the correct answer is
the coil inside the heater may melt and break.
Answer:
here you go
Explanation:
The reaction of phenol with bromine is known as bromination of phenol. Solvent has great influence on the reaction. In different solvents, different products are obtained. The action of bromine on phenol can be explained as:
Reaction with bromine in water:—-
Reaction with bromine in water
Phenol reacts with bromine water to give 2,4,6-tribromophenol.
In water, ionisation is facilitated. Phenol gets ionised to form phenoxide ion, which is even better ortho,para-directing. Bromine also gets ionised to a larger extent to form a large number of bromonium ions. And Bromine ions are highly stabilized in ionic solvents. So the formation of strong o,p-directing group and stabilization of Br+ enhances the formation of tribromophenol.
Reaction with bromine in CS2:—-
Reaction with bromine in non-polar organic solvents
Phenol reacts with bromine in a presence of Carbon disulphide to form a mixture of o-bromophenol and p-bromophenol. Among which p-bromophenol predominates. In CS2 ionisation is not facilitated that much. As it is a non-polar solvent it doesn't the Br+ on. Also −OH group is moderately o,p-directing. So as usual para-product is more formed.
The ideal gas law formula is: PV=nRT. As the n(moles of gas), R(Gas constant) and T(temperature) values are constant as it is given in the problem, we can calculate the pressure difference by the following formula: xΔP(difference factor of pressure)=1/xΔV. We can find the difference factor of volume by x=V(0)/v(1),
x=18l/2l=9 which means the pressure is 9 times greater after the volume is down to 2l. To find the final pressure, we can use P(1)=xP(0), when we add the numbers in, it looks like this: P(1)=9*42 kPa=378 kPa
