Answer: 310K
Explanation:
Given that:
Volume of Chlorine gas V = 10.2L
Temperature T = ?
Pressure P = 1.83 atm
Number of moles of chlorine gas N = 0.734 moles
Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
1.83atm x 10.2L= 0.734 moles x 0.0821 atm L K-1 mol-1 x T
18.67atm L = 0.0603 atm L K-1 x T
T = (18.67atm L / 0.0603 atm L K-1)
T = 309.8K (Round up to 310K)
Thus, the temperature of the chlorine gas is 310 kelvin
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ΔH=MCΔT
ΔH=100 x 4.2 x 4
ΔH=1680
ΔH per mole = ΔH ÷ moles
ΔH per mole = 1680 ÷ 0.02
<span>ΔH per mole= 84000Jmol
</span>84000 ÷ 1000 = 84KJmol
its exothermic as heat is given out into the solution
Answer:
CH4+ 2Cl2→CH2Cl2+ 2HCl
Explanation:
mass is 132.8`125
as methane and dichlormethane has the same molar ration 1 to 1
mol of ch4 is 1.5625
so 1.5625 times mr of ch2cl2 is 132.8125