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Anna35 [415]
3 years ago
13

How many molecules of oxygen are in 3.0 moles of oxygen?

Chemistry
2 answers:
Daniel [21]3 years ago
7 0

Answer:

18.066× 10²³ molecules

Explanation:

Given data:

Number of moles of oxygen = 3.0 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

3 mol  × 6.022 × 10²³ molecules  / 1 mol

18.066× 10²³ molecules

jenyasd209 [6]3 years ago
5 0

Answer:

There are 18 moles of oxygen in 3.0 mole of glucose...

Explanation:

Does it help???

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Nadusha1986 [10]

Answer:

Try quizlet, they have everything on there

Explanation:

8 0
3 years ago
Describe the three types of system: a.open: b.closed: c. Isolated:
Mnenie [13.5K]

An open system is when there is a transfer of energy and matter with its surroundings.

A closed system is where there is a transfer of energy, may it be heat or work, but not matter with its surroundings.

An isolated system is where there is no transfer of energy or matter with its surroundings.

4 0
3 years ago
To what temperature in kelvin will a 2.3 L balloon have to be heated to expand to a volume of 400 L Assume the initial temperatu
olchik [2.2K]

Answer:

T₂ = 51826.1 K

Explanation:

Given data:

Initial Volume = 2.3 L

Final volume = 400 L

Initial temperature = 25 °C (25+ 273 = 298 K)

Final temperature = ?

Solution:

V₁/T₁ = V₂/T₂

T₂ = V₂ T₁/V₁

T₂ =  400 L . 298 K / 2.3 L

T₂ = 119200 K. L / 2.3 L

T₂ = 51826.1 K

7 0
3 years ago
5. Determine the number of liters in 4.32 grams of water (H2O). Answer: --_ 5.37L H2O__​
MariettaO [177]

Answer:

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Explanation:

22.4 is how many liters per mole. 18.01 is the mass of H2O.

8 0
3 years ago
CO2(s) → CO2(g)
Vesnalui [34]

Answer: entropy, increase

Explanation:

During the sublimation of carbon dioxide, the disorder and the entropy of the system increase. Hope this works :)

4 0
4 years ago
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