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babunello [35]
3 years ago
6

Hook GC lsshvrrjvdjscavsbsgd​

Chemistry
1 answer:
Tema [17]3 years ago
6 0

Answer:

I have no idea what that issss

Explanation:

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Petroleum is a mixture of many alkanes. The alkanes are separated and purified at oil refineries. What process decribes what hap
Elanso [62]

Answer:

Fractional distillation

Explanation:

The process of separating petroleum products into its fractions is called fractional distillation.

Fractional distillation is a method of separating a mixture of substances based on the differences in their boiling points.

Petroleum is a mixture of hydrocarbons separated in a large fractionation tower having many trays maintained at different temperatures.

As the vapor containing the petroleum mixture ascends the fractionation tower, the mixture is separated at each tray to yield the various fractions of petroleum.

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Which of the following is true about gravity? <br><br> Select all that apply.
Ivenika [448]

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Read 2 more answers
A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at
Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0
3 years ago
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