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yKpoI14uk [10]
4 years ago
5

The relationship between pressure and volume, when moles and temperature of a gas are held constant, is: PV = k. We could say th

en, that:
If the volume of the gas is doubled, the pressure also doubles.
If the volume of a gas is halved, the pressure is doubled.
If the volume of gas is doubled, the pressure is unaffected.
If the volume of a gas is halved, the pressure is tripled.
Chemistry
1 answer:
pochemuha4 years ago
7 0
You can say that if the volume of the gas is halved, the pressure is doubled.

The expression shows that pressure and volume are inversely proportional if temperature and amount of gas is held constant.  This means that if volume goes down the pressure needs to go up.  That also means that in order to maintain the K value, if pressure is doubled the volume needs to be halved and if the pressure is halved the volume needs to be doubled.

This relationship only works if we assume everything else (Temperature and moles of gas) to be constant.
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3 years ago
To determine the concentration of chloride ion (Cl-) in a 100 mL sample of ground water, a chemist adds a large enough volume of
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Answer:

[Cl^-]=232.3\frac{mgCl^-}{L}

Explanation:

Hello,

In this case, we can represent the chemical reaction as:

Cl^-(aq)+AgNO_3(aq)\rightarrow AgCl(s)+NO_3^-(aq)

In such a way, since the mass of the obtained silver chloride is 93.9 mg, we can compute the chloride ions in the ground water by using the following stoichiometric procedure whereas the molar mass of chloride ions and silver chloride are 35.45 g/mol and 143.32 g/mol respectively:

m_{Cl^-}=93.3mgAgCl*\frac{1mmolAgCl}{143.32mgAgCl}*\frac{1mmolCl^-}{1mmolAgCl} *\frac{35.45mgCl^-}{1mmolCl^-} =23.23mgCl^-

Finally, for the given volume of water in liters (0.100L), we compute the required concentration:

[Cl^-]=\frac{23.2mgCl^-}{0.100L}\\

[Cl^-]=232.3\frac{mgCl^-}{L}

Best regards.

5 0
4 years ago
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