3:00m cu of the current in electrical engineering and electrical toques
Answer:
2. ![V_2=17L](https://tex.z-dn.net/?f=V_2%3D17L)
3. ![V=82.9L](https://tex.z-dn.net/?f=V%3D82.9L)
Explanation:
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2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:
![\frac{V_2}{T_2}=\frac{V_1}{T_1}](https://tex.z-dn.net/?f=%5Cfrac%7BV_2%7D%7BT_2%7D%3D%5Cfrac%7BV_1%7D%7BT_1%7D)
Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:
![V_2=\frac{V_1T_2}{T_1}](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7BV_1T_2%7D%7BT_1%7D)
Therefore, we plug in the given data to obtain:
![V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7B18.2L%2822%2B273%29K%7D%7B%2845%2B273%29K%7D%20%5C%5C%5C%5CV_2%3D17L)
3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:
![V=\frac{nRT}{P}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BnRT%7D%7BP%7D)
Therefore, we plug in the data to obtain:
![V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B3.7mol%2A0.08206%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A273.15K%7D%7B1atm%7D%5C%5C%5C%5CV%3D82.9L)
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Answer:
Water ______________________________________________
Answer:
Limitations of Rutherford Atomic Model
Although the Rutherford atomic model was based on experimental observations it failed to explain certain things. Rutherford proposed that the electrons revolve around the nucleus in fixed paths called orbits. ... Ultimately the electrons would collapse in the nucleus.