All categories

2 years ago

What do halo stars do differently from disk stars?

1 answer:

6 0

Answer: They orbit the galactic center with many different inclinations, while disk stars all orbit in nearly the same plane. ... They have vertical motions out of the plane, making them appear to bob up and down, but they never get "too far" from the disk.

Explanation:

You might be interested in

Bank A has a leverage ratio of 10, while Bank B has a leverage ratio of 20. Similar losses on bank loans at the two banks cause

tamaranim1 [39]

Answer:

note:

find the attached solution:

3 0

3 years ago

What would be most useful to help make a simple compass a nonmetal bar,a round metal can,a small iron nail,or a Quartz needle

pav-90 [236]

Iron nail. the rest of those are not iron or some form of magnetic material.

5 0

3 years ago

Read 2 more answers

Question 7 of 10 A permanent magnet picks up an iron nail, magnetizing the nail. How is this system different from an electromag

Nookie1986 [14]

Answer: I think it’s D i really hope this helps!!!!

Explanation:

5 0

3 years ago

A 1,100 kg car is traveling initially 20 m/s when the brakes are applied. The brakes apply a constant force while bringing the c

Natalka [10]

Answer:

Work done = -220,000 Joules.

Explanation:

Given the following data;

Mass = 1100kg

Initial velocity = 20m/s

To find workdone, we would calculate the kinetic energy possessed by the car.

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

$K.E = \frac{1}{2}MV^{2}$

Where,

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the equation, we have;

$K.E = \frac{1}{2}*1100*20^{2}$

$K.E = 550*400$

K.E = 220,000J

Therefore, the workdone to bring the car to rest would be -220,000 Joules because the braking force is working to oppose the motion of the car.

4 0

2 years ago

In the great shopping cart race, two students push on shopping carts. A having twice the mass of B, with the same force applied

Lesechka [4]

K = 1/2 m x v^2

m = mass on the cart

V = velocity imparted to the cart

KA = 1/2 mA x vA^2.......................(1)

KB = 1/2 mB x vB^2........................(2)

Diving equation 1 by equation 2, we get -

KA/KB = mA/mB

= 2

KA = 2 x KB

Option A is correct

6 0

3 years ago