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Otrada [13]
3 years ago
7

Drag the labels to the table below to describe how allele frequencies would be affected under different conditions. remember tha

t p is the frequency of the cr allele, and q is the frequency of the cw allele. labels may be used once, more than once, or not at all.
Physics
2 answers:
zaharov [31]3 years ago
7 0
This the correct answer for this question:
Mutation - p will  increase and q will decrease

Nonrandom mating - frequency of plants with pink flowers will be much less than 2pq

Natural selection - p and q will stay the same

Small population size - changes in p and q cannot be predicted

Gene flow - p will decrease and q will increase
gizmo_the_mogwai [7]3 years ago
3 0
This the correct answers for this question:

Mutation - p will  increase and q will decrease

In this case, "P" is representing homozygosity "Q" is representing genetic variation. Therefore the individuals are further decreasing genetic variation by increasing homozygosity in the genomes of their offspring. Mutation is a weak force for changing allele frequencies but is a strong force for introducing new alleles therefore it is the ultimate source of new alleles in plant pathogen populations. 
Nonrandom mating - Frequency of plants with pink flowers will be much less than 2pq
Nonrandom mating<span> occurs when the probability that two individuals in a population will mate is not the same for all possible pairs of individuals.
</span>
Natural selection - p and q will stay the same

The interactions between individuals and their environment are what determines whether their genetic information will be passed on or not. The sum of the allele frequencies for all the alleles at the locus must be 1, so p + q = 1.

Small population size - Changes in p and q cannot be predicted

Small populations tend to lose genetic diversity more quickly than large populations due to stochastic sampling error

Gene flow - p will decrease and q will increase

Migrants result change the distribution of genetic<span> diversity within the populations, by modifying the allele frequencies. </span>
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Hook's law states that:

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F=mg=(2.0 kg)(9.8 m/s^2)=19.6 N

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Solving eq.(1) for k, we find the spring constant:

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If a block of m = 3.0 kg is attached to the spring, the new force applied is

F=mg=(3.0 kg)(9.8 m/s^2)=29.4 N

And so, the stretch of the spring is

\Delta x=\frac{F}{k}=\frac{29.4 N}{392 N/m}=0.075 m=7.5 cm

And since the initial lenght of the spring is

x_0 = 10 cm

The final length will be

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8 0
3 years ago
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Ksivusya [100]

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Explanation:

We can solve this problem by using Newton's second law, which states that the net force on an object is equal to the product between its mass and its acceleration:

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Learn more about Newton's second law:

brainly.com/question/3820012

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