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patriot [66]
3 years ago
9

A 1460-kg submarine rises straight up towards the surface. Seawater exerts both an upward buoyant force of 16670 N on the submar

ine, as well as a downward resistive force of 1150 N. What is the submarine's acceleration?
Physics
1 answer:
Amiraneli [1.4K]3 years ago
5 0

Answer:

a = 0.63 m/s²

Explanation:

given,

mass of submarine = 1460-kg

upward buoyant force = 16670 N

downward resistive force = 1150 N

submarine acceleration = ?

assuming g = 10 m/s²

now,

B - (R + mg) = ma

16670 - 1150 - 1460 × 10 = 1460 × a

1460× a = 920

a = 0.63 m/s²

hence, the acceleration of submarine is equal to a = 0.63 m/s²

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What is the average speed of a cheetah that runs 88 m in 5 seconds
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<h3>Introduction</h3>

Hello ! I'm Deva from Brainly Indonesia. This time, I will help regarding the average speed. The average speed is obtained from finding the average of the speeds that occur or can be detected from the division between distance and travel time. The average speed can be formulated by :

\boxed{\sf{\bold{\overline{v} = \frac{s}{t}}}}

With the following condition :

  • \sf{\overline{v}} = average speed (m/s)
  • s = shift or distance objects from initial movement (m)
  • t = interval of the time (s)

<h3>Problem Solving</h3>

We know that :

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What was asked :

  • \sf{\overline{v}} = average speed = ... m/s

Step by step :

\sf{\overline{v} = \frac{s}{t}}

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