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lesya692 [45]
3 years ago
5

1) A rock thrown horizontally from the top of a

Physics
1 answer:
9966 [12]3 years ago
3 0
Dx = 20m
V1 = 10m/s
g = 9.8m/s^2
(delta-t) = 2sec
dy = 19.6m 
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Where is this image?

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Saying no and not throwing fits and manners.
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Runner A is initially 5.7 km west of a flagpole and is running with a constant velocity of 8.9 km/h due east. Runner B is initia
Oksanka [162]

Answer:

B meet A 0.01 km east of flagpole

Explanation:

given data

distance A = 5.7 km  west

velocity V1 = 8.9 km/h

distance B = 4.5 km  east

velocity V2 = 7 km/h

to find out

How far runners from the flagpole, when paths cross

solution

we know A and B are 5.7 + 4.5 = 10.2 km apart

and we consider here B will run distance x km for meet

so time will be for B is

time B = distance / velocity

time B = x / 7     ...................1

and

for A distance for meet = ( 10.2 - x ) km

so time A = distance / velocity

time A = ( 10.2 - x )  / 8.9      .............2

now equating equation 1 and 2

time A = time B

x / 7  =   ( 10.2 - x )  / 8.9

x = 4.490

so distance of B run for meet is 4.490 km

so distance from the flagpole when their paths cross is 4.5 - 4.490 = 0.01 km

so B meet A 0.01 km east of flagpole

4 0
3 years ago
Eva makes a graphic organizer to compare electromagnets with solenoids. A venn diagram with 2 intersecting circles. The circle o
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The metalcore is the central component of any metal that is covered by wires. Metalcore is found in the X denoted area.

<h3>What is a solenoid?</h3>

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When a conductive wire is used to build a loop, a solenoid is formed.

Hence the metalcore is found in the given X area.

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3 years ago
A dime is placed in front of a concave mirror that has a radius of curvature R = 0.40 m. The image of the dime is inverted and t
andrew11 [14]

Answer:

distance between the dime and the mirror, u = 0.30 m

Given:

Radius of curvature, r = 0.40 m

magnification, m = - 2 (since,inverted image)

Solution:

Focal length is half the radius of curvature, f = \frac{r}{2}

f = \frac{0.40}{2} = 0.20 m

Now,

m = - \frac{v}{u}

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Now, by lens maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

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From eqn (2):

v = 2u

put v = 2u in eqn (3):

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2 = \frac{f}{u - f}

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6 0
3 years ago
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