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3 years ago

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You are to write a program name elevator.java that simulates one elevator services in a 12-floor building. note: there is only o

ne elevator working this building.

Computers and Technology

1 answer:

gogolik [260]3 years ago

5 0

See the attachment, if I copy if it into the Response field it gets all jumbled. Rename it to elevator.java

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Think back over the information presented in the lesson about how you can skillfully use the Internet when doing research. Selec

madreJ [45]

Avoid wikipedia, anyone can put answers down on there and make it seem correct but it is not. Do not trust any website research the websites or look at ratings if possible. Use the answers that google provides itself if possible. And research trusted websites.

If this helped please mark me as brainlest.

$\left[\begin{array}{ccc}Thanks,\\JustSomeIdiot\end{array}\right]$

7 0

3 years ago

What are the first and the last physical memory addressesaccessible using

Misha Larkins [42]

Answer

For First physical memory address,we add 00000 in segment values.

For Last physical memory address,we add 0FFFF in segment values.

<u>NOTE</u>-For addition of hexadecimal numbers ,you first have to convert it into binary then add them,after this convert back it in hexadecimal.

a)1000

For First physical memory address, we add 00000 in segment value

We add 0 at the least significant bit while calculating.

1000<u>0</u> +00000 = 1000<u>0</u> (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

1000<u>0</u> +0FFFF =1FFFF (from note)

b)0FFF

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

0FFF<u>0</u> +00000=0FFF0 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

0FFF<u>0</u> +0FFFF =1FFEF (from note)

c)0001

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

0001<u>0</u> +00000=00010 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

0001<u>0</u> +0FFFF =1000F (from note)

d) E000

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

E000<u>0</u> +00000=E0000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

E000<u>0</u> +0FFFF =EFFFF (from note)

e) 1002

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

1002<u>0</u> +00000=10020 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

1002<u>0</u> +0FFFF =2001F (from note)

6 0

3 years ago

We are building a word processor and we would like to implement a "reflow" functionality that full-justifies text.Given a maximu

adoni [48]

Answer:

The code is given below in Java with appropriate comments

Explanation:

Reflow is an function which helps you to justify your functionality

You need to input a string array and the max width and you will get the

output in a list(string).

public List<String> Reflow(String[] input, int width) {

List<String> result = new ArrayList<String>();

if(input==null || input.length==0){

return result;

}

int count=0;

int last=0;

ArrayList<String> list = new ArrayList<String>();

for(int i=0; i<input.length; i++){

count = count + input[i].length();

if(count+i-last>width){

int wl = count-input[i].length();

int sl = maxWidth-wl;

int each = 1;

int el = 0;

if(i-last-1>0){

each = sl/(i-last-1);

el = sl%(i-last-1);

}

StringBuilder sb = new StringBuilder();

for(int k=last; k<i-1; k++){

sb.append(input[k]);

int ce = 0;

while(ce<each){

sb.append(" ");

ce++;

}

if(el>0){

sb.append(" ");

el--;

}

}

sb.append(input[i-1]);//last input in the line

//if only one word in this line, need to fill left with space

while(sb.length()<width){

sb.append(" ");

}

result.add(sb.toString());

last = i;

count=input[i].length();

}

}

int lastLen = 0;

StringBuilder sb = new StringBuilder();

for(int i=last; i<input.length-1; i++){

count = count+input[i].length();

sb.append(input[i]+" ");

}

sb.append(input[input.length-1]);

int d=0;

while(sb.length()<maxWidth){

sb.append(" ");

}

result.add(sb.toString());

return result;

}

6 0

3 years ago

1. What does it mean to say that a country’s land area is positively correlated with its population?

disa [49]

For 1.
Positive correlation means if you plot a country's population and land size on a graph. There would be a linear regression line that's sloping upwards.

Since it's a scatterplot, there will be some that fall out of the line, but most of them should be on the line.

It's (A)

For 2.
An outlier is a datapoint that's far, FAR away from the others, so it's (B)

For 3. (A), it's a single line-of-best fit that runs through the middle of the cluster of data points.

5 0

3 years ago

Read 2 more answers

Suppose that the format for license plates in a certain state is two letters followed by four numbers. (a) How many different pl

Ymorist [56]

Answer:

(a) 6,760,000 plates

(b) 3,407,040 plates

(c) 6,084,000 plates

Explanation:

The very first thing to note about this question is the number of characters involved in the license plate format (6 characters in this case; 2 letters and 4 numbers). The letters come first and then the numbers follow.

There are a total of 26 possible letters (A-Z) and 10 possible numbers (0 - 9) that can be chosen. We can then proceed to the first question;

(a) Here, the total number of possible plates is to be determined. This is done as follows:

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

Character 3 (number): There are 10 possible numbers

Character 4 (number): There are 10 possible numbers

Character 5 (number): There are 10 possible numbers

Character 6 (number): There are 10 possible numbers

So, total number of different plates will be obtained by multiplying all the possibilities: 26 × 26 × 10 × 10 × 10 × 10 = 6,760,000 plates

(b) This second part puts a constraint on the usage of the numbers, unlike the question (a), where there was no constraint at all.

Since there is no constraint on the letters, we can write that:

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

For the first number as well, we can write:

Character 3 (number): There are 10 possible numbers

However, for the remaining characters, the possibilities will continually reduce by a value of 1, since we can not use a number that has been used before. So,

Character 4 (number): There are 9 possible numbers

Character 5 (number): There are 8 possible numbers

Character 6 (number): There are 7 possible numbers

So, total number of different plates will be: 26 × 26 × 10 × 9 × 8 × 7 = 3,407,040 plates

(c) Here, repetitions are allowed as in questions (a), but there can not be four zeros. This implies that the maximum number of zeros in any plate will be three. Thus, there will be maximum possibilities on all characters until the last one which will be constrained.

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

Character 3 (number): There are 10 possible numbers

Character 4 (number): There are 10 possible numbers

Character 5 (number): There are 10 possible numbers

Character 6 (number): There are 9 possible numbers

Total number of plates will therefore be: 26 × 26 × 10 × 10 × 10 × 9 = 6,084,000 plates.

7 0

3 years ago