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raketka [301]
3 years ago
14

Barium chlorate (Ba(ClO3)2) breaks down to form barium chloride and oxygen. What is the balanced equation for this reaction? Whe

n counting atoms in parentheses multiply all subscripts by the number outside the parentheses to get the number of atoms
Chemistry
2 answers:
LekaFEV [45]3 years ago
6 0

Answer:

C

Explanation:

Maksim231197 [3]3 years ago
5 0

Answer:

Ba(ClO3)2 → BaCl2 + 3O2

Explanation:

According to this question, Barium chlorate (Ba(ClO3)2) breaks down to form barium chloride (BaCl2) and oxygen (O2). The equation is as follows:

Ba(ClO3)2 → BaCl2 + O2

One would notice that this equation is not BALANCED because the number of atoms of each elements are not the same on each side of the equation.

- There is one atom of Barium (Ba) on both reactants and product side

- There are two atoms of chlorine (Cl) on both reactants and product side

- There is an unven number of atoms of oxygen on both sides. That is, 6 atoms of oxygen on reactant side but 2 atoms on product side.

To balance the number of oxygen atom, we add coefficient 3 to the oxygen atom on the product side to have 6-6 for both sides. That is;

Ba(ClO3)2 → BaCl2 + 3O2

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