Answer:
Ba(ClO3)2 → BaCl2 + 3O2
Explanation:
According to this question, Barium chlorate (Ba(ClO3)2) breaks down to form barium chloride (BaCl2) and oxygen (O2). The equation is as follows:
Ba(ClO3)2 → BaCl2 + O2
One would notice that this equation is not BALANCED because the number of atoms of each elements are not the same on each side of the equation.
- There is one atom of Barium (Ba) on both reactants and product side
- There are two atoms of chlorine (Cl) on both reactants and product side
- There is an unven number of atoms of oxygen on both sides. That is, 6 atoms of oxygen on reactant side but 2 atoms on product side.
To balance the number of oxygen atom, we add coefficient 3 to the oxygen atom on the product side to have 6-6 for both sides. That is;
Ba(ClO3)2 → BaCl2 + 3O2
