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Greeley [361]
3 years ago
13

Graph the function. y = 1/5 (3)^x Graph A. B. C. or D?

Mathematics
1 answer:
patriot [66]3 years ago
8 0

The function y=3^x is incresing and have positive values for all x. Then the function y=\dfrac{1}{5}\cdot 3^x is also increasing and have positive values for all x. This means that options B (values are negative) and D (function is decreasing) are incorrect.

At x=0, y=\dfrac{1}{5} \cdot 3^x=\dfrac{1}{5} \cdot 3^0=\dfrac{1}{5} \cdot 1=\dfrac{1}{5}.

In option A graph of the function passes through point (0,y), where y is near 3. In option C graph of the function passes through point (0,y), where y is near 1/5. So, you can conclude that the option C is correct.

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PLEASE HELP! The formula F = 95C + 32, where C stands for temperature in degrees Celsius, is used to convert Celsius to Fahrenhe
Masteriza [31]

The temperature is 86°F when the temperature is 30°C.

Step-by-step explanation:

Formula for Celsius to Fahrenheit;

F = F=\frac{9}{5}C+32

Where C stands for temperature in degrees Celsius.

Given,

Temperature in Celsius = 30 degrees

Temperature in Fahrenheit = \frac{9}{5}*30+32

Temperature in Fahrenheit = 9*6+32

Temperature in Fahrenheit = 54+32 = 86\ degrees\ Fahrenheit

The temperature is 86°F when the temperature is 30°C.

Keywords: temperature, addition

Learn more about addition at:

  • brainly.com/question/1465430
  • brainly.com/question/1466393

#LearnwithBrainly

7 0
3 years ago
Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r
PolarNik [594]

Answer:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

(a-b)^2=a^2-2ab+b^2

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}

\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8

\displaystyle b=\frac{1}{7}mpz^4

Nos cercioramos de que el término central es 2ab:

\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4

Operando:

\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5

Una vez verificado, ahora podemos decir que:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

5 0
3 years ago
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slavikrds [6]

Step-by-step explanation:

6k + 12 + 9=9

6k + 12 = 9 - 9

6k + 12 = 0

12 = -6k

12/-6 = -6k/-6

2/-1 = k

k = -2

6 0
3 years ago
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Hope this helped the answer is in purple

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