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Citrus2011 [14]
3 years ago
15

PLEASE HELP, I ONLY NEED THE RIGHT ANSWER IN LITERS

Chemistry
1 answer:
grandymaker [24]3 years ago
6 0
You can form 9.20 L of NH₃ gas at 93.0 °C and 37.3 kPa or 2.56 L at STP. The balanced chemical equation is N₂ + 3H₂ → 2NH₃ Since all substances are gases, we can use litres instead of moles in our calculations. You don't specify the pressure and temperature of the NH₃, so I will calculate its volume in two ways. 
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At a certain temperature, the equilibrium constant, Kc, for this reaction is 53.3 At this temp, 0.3000 mol of H2 and 0.300 mol o
Vlada [557]
Your answer is: Kc = [HI]² / {[H2] [I2]} 
<span>53.3 = (2x)² / {(0.400M - x)(0.400M - x)} </span>
<span>sqrt(53.3) = 2x / (0.400M - x) </span>
<span>2.92 - 7.30x = 2x </span>
<span>x = 0.314M </span>

<span>[HI] = 2x = 0.628M

:) hopefully this helped. (:</span>
4 0
3 years ago
What chemical change occurred in the following reaction? Mg2+(aq)+2OH−(aq)⟶ Mg(OH)2(s)
irina1246 [14]
I think it might be a gas was formed.
Hope I'm right and it helps you out!!
6 0
3 years ago
Read 2 more answers
What mass of NaOH is in 3.0e+02 mL of a 5.0 M NaOH solution?
Snezhnost [94]
Answer is: mass of sodium hydroxide is 60 grams.
V(NaOH) = 300 mL · 1 L/1000mL = 0,3 L.
c(NaOH) = 5 M = 5 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 5 mol/L · 0,3 L.
n(NaOH) = 1,5 mol.
m(NaOH) = n(NaOH) · M(NaOH).
m(NaOH) = 1,5 mol · 40 g/mol.
m(NaOH) = 60 g.
3 0
2 years ago
4. What is percent error calculation used to determine?
madam [21]

Answer:

Explanation:

You could use it for many things but one thing people use it for is the percent of failure when bonding bonds such as ionic bonds in chemistry.

3 0
2 years ago
Help I WILL AWARD BRAINLIEST
professor190 [17]

Answer:

see the pic for the answer

7 0
2 years ago
Read 2 more answers
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