2 years ago

These are two similar triangles

Mathematics

1 answer:

Charra [1.4K]2 years ago

5 0

I believe the answer should be 18. Try

You might be interested in

Two girls were competing in 100 meter dash. The first girl ran it in 14.47 seconds. The second girl ran it in 13.88 seconds. How

Butoxors [25]

Answer:

the second girl was. 59 seconds faster than the first girl.

Step-by-step explanation:

14.47-13.88= .59

8 0

3 years ago

Create a linear, quadratic, and cubic function that all have solutions at (-5,32)

OleMash [197]

This is the leineae making it a because it’s cubic

6 0

3 years ago

NEED HELL ASAP WILL GIVE BRAINLY algebra 1

Lesechka [4]

Answer:

x - 6 = 24

Step-by-step explanation:

1/3 x - 2 = 8

Multiply all the terms by 3

3*1/3x - 2*3 = 8*3

x - 6 = 24

4 0

3 years ago

Read 2 more answers

How to find the length of line BD

Artemon [7]

The answer would probably be D because you don't know what x is.

6 0

3 years ago

Read 2 more answers

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

5 0

3 years ago