Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So



has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
(7+4i)+0=7+4i.
Hope it helps
Answer:
b
Step-by-step explanation:
Certificates of deposit are only available to the bank's most proven and valuable customers, so the bank can afford to give a greater interest rate on them.
Let us solve for the total area. In this problem, we solve area 1 (the rectangle in the middle) and the area 2 ( the two half circle on the sides).
Solve for area 1:
Area rec = L * W = 5units * 4 units = 20 squared units
Solve for area 2:
Area cir = pi *r² = 3.14 * (2 units)² = 12.56 squared units
Total area = 20 + 12.56 = 32.56 foot²
Total cost = 32.56 foot² * ($23/foot²) = $ 748.88
Total cost is $748.88.