Please Help, This is confusing. What is the equation of the line that passes through the point (2,-6) and has a slope of -1?

Mathematics

2 answers:

vovangra [49]3 years ago

8 0

Answer:

ok ok it is y+6=-1(x-2)

Step-by-step explanation:

brainliest?

omeli [17]3 years ago

4 0

Answer:

Firstly, you can use the slope and the first point to find a second point:

2 + 1 = x2 and 6 + 5 = y2 because the slope is 5/1.

Next you can write the equation in point-slope form (remember point-slope form is y - y1 = m(x - x1):

y - 11 = 5(x - 3)

Another equation would be B because B is the correct equation if you choose 2 as x2 and 6 as y2.

Hope this helps!

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strojnjashka [21]

Answer:

x = 0

Step-by-step explanation:

${2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {9}^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {( {3}^{2}) }^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {({3)}^{2x}}}\\ \\ {2}^{x} - \cancel{{3}^{x}} = \sqrt{ {6}^{x} } - \cancel{ {3}^{x} } \\ \\ {2}^{x} = \sqrt{ {6}^{x} } \\ squaring \: both \: sides \\ \\ {( {2}^{x} )}^{2} = {(\sqrt{ {6}^{x} })}^{2} \\ \\ {2}^{2x} = {6}^{x} \\ \\ {2}^{2x} = {(2 \times 3)}^{x} \\ \\ {2}^{2x} = {2 ^{x} \times 3}^{x} \\ \\ \frac{ {2}^{2x} }{ {2}^{x} } = 3^{x} \\ \\ {2}^{2x - x} = {3}^{x} \\ \\ {2}^{x} = {3}^{x} \\ \\ \frac{ {2}^{x} }{ {3}^{x} } = 1 \\ \\ \bigg( \frac{2}{3} \bigg)^{x} = 1 \\ \\ \implies \: x = 0 \\ \\ \because \: for \: x = 0 \\ \\ \bigg( \frac{2}{3} \bigg)^{0} = 1$