Answer:
Step-by-step explanation:
Both equations should be in slop-intercept form (y=mx+b)
So add -2x to -6. Your equation should look like this
y=2x-6
In y=mx+b
b will fall on y-axis
mx is rise/run
So in the first equation plot -6 on y axis and go up 2 and over 1(because 2x is equivalent to 2/1 x)
In the second equation plot -1 on the y axis. Then go up 1 and over 3 from that point.
*the table being referred to is attached below
Answer:
The table does not show a proportional relationship between variable g and h.
Step-by-step explanation:
For a proportional relationship to exist between two variables, there must be a constant, of which serves like a unit rate, when comparing two variables.
Thus, in the table attached below, there is no obvious constant of proportionality between variable g and variable h.
Thus, ≠
≠
We have been given that Darren invests $4,500 into an account that earns 5% annual interests. We are asked to find the amount in his account after 10 years, if the interest rate is compounded annually, quarterly, monthly, or daily.
We will use compound interest formula to solve our given problem.
, where,
A = Final amount,
P = Principal amount,
r = Annual interest rate in decimal form,
n = Number of times interest is compounded per year,
t = Time in years.
When compounded annually, :
When compounded quarterly, :
When compounded monthly, :
When compounded daily, :
Since amount earned will be maximum, when interest is compounded daily, therefore, Darren should use compounded daily interest rate.
Step-by-step explanation:
for number 8. The slope is -3 because the standard form equation is y=mx+c. And we know that m represents your slope.
Hence why it is -3.
For number 10. The slope is 0. I Forgot to write that on the pic
:)
Answer:
C. x ≈ 0.28
Step-by-step explanation:
A graphing calculator solution is attached. It shows ...
x ≈ 0.28
__
You can divide both sides of the given equation by 5, then take natural logs and divide by 5 again.
5e^(5x) = 20 . . . . . . given
e^(5x) = 4 . . . . . . . . divide by 5
5x = ln(4) . . . . . . . . take natural logs
x = ln(4)/5 . . . . . . . divide by 5
x ≈ 0.277259 ≈ 0.28
