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Gnoma [55]
2 years ago
13

NEED HELP FAST y=−1/3x+1

Mathematics
2 answers:
fgiga [73]2 years ago
4 0

\\ \sf\longmapsto y=\dfrac{-1}{3}x+1

Here let's compare with slope intercept form

\\ \sf\longmapsto y=mx+b

We get

  • Slope=m=-1/3
  • y-intercept=b=1
Zigmanuir [339]2 years ago
3 0

y = mx + k

gradien = m

y=−1/3x+1

gradien = -1/3

btw, di indo jg ada gradien :)

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\bold{\huge{\green{\underline{ Solution }}}}

\bold{\underline{ Given}}

  • <u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

\bold{\underline{To  \: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

\bold{\underline{Let's \:  Begin :- }}

The coordinates of G = ( -6 , 5 )

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<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}

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<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>

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\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}

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