Christy should make at least 30 bracelets and at most 40 necklaces to maximize profit
<h3>How to determine how many bead of each type of bracelets and necklaces should Christy make to maximize his profit?</h3>
The given parameters can be represented in the following tabular form:
Bracelet (x) Necklace (y) Total
Labor (hour) 0.5 0.75 40
Profit 10 18
From the above table, we have the following:
Objective function:
Max P = 10x + 18y
Subject to:
0.5x + 0.75y <= 40
Because she wants to make at least 30 bracelets, we have:
x >= 30
So, we have:
Max P = 10x + 18y
Subject to:
0.5x + 0.75y <= 40
x >= 30
Express x >= 30 as equation
x = 30
Substitute x = 30 in 0.5x + 0.75y <= 40
0.5 * 30 + 0.75y <= 40
This gives
15 + 0.75y <= 40
Subtract 15 from both sides
0.75y <= 30
Divide by 0.75
y <= 40
Hence, Christy should make at least 30 bracelets and at most 40 necklaces to maximize profit
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The answer is b because 6 and 4s common denominator is 24
Side JL is 4√2 recall that in a 30-60-90 right triangle the hypotenuse is 2 times the size of the short leg.
JL also serves as the hypotenuse of the 45-45-90 triangle JML. The ratio of side lengths in this triangle is 1:1:√2
So we can see that the value of x = 4
A fair coin just means 50% heads 50% tails. so the sample is still 50% heads 50% tails.