The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
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Answer:
9
Step-by-step explanation:
UT^2 = UV * UW
6^2 = (x - 7)(x - 7 + 5)
36 = (x - 7)(x - 2)
36 = x^2 - 2x - 7x + 14
x^2 - 9x - 22 = 0
(x - 11)(x + 2) = 0
x - 11 = 0 or x + 2 = 0
x = 11
UW = x - 7 + 5
UW = 11 - 7 + 5
UW = 9
The length would be 6 and the width would be 4 to get 24 as the area.
Answer:
1.01 minutes
Step-by-step explanation:
The length of the roll is given to be 304 ft, and Bob's velocity is 5ft/s.
Velocity is defined as the rate of change of displacement over time t:
The function can be expressed to make t the subject to calculate time taken by Bob;
Hence, it takes Bob 1.01 minutes to walk the length of the roll.
The median is 12.
The arithmetic mean is 12.7
The geometric mean is 11.3
