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3 years ago

Write the relation as a set of ordered pairs. WILL MARK BRANLIEST!! PLEASE HELP ASAP!!!!

Mathematics

2 answers:

dsp733 years ago

8 0

Answer:

Option a.

Step-by-step explanation:

An ordered pair is written in the following form: (x, y). It means, first the independent variable and secondly the dependent variable.

In the diagram, the first circle represents the independent variable, and the second circle represents the dependent variable.

Then, the set of ordered pairs is (From left to right)

(-3, 3) ; (0, 0) ; (2, -2).

So the correct option is option a.

butalik [34]3 years ago

3 0

Answer:

The correct answer is option a

(-3, 3), (0, 0) and (2, -2)

Step-by-step explanation:

From the figure we can see three points are marked.

Each points can be written as ordered pair (x, y)

From left to right we can write,

the three pots are,

(-3, 3), (0, 0) and (2, -2)

Therefore the correct answer is option a

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Neil goes to the pet shop and

umka2103 [35]

Answer:

b (1/15)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

ATTENTION: Please help! I will give BRAINLIEST to who ever is right AND will give 10 points AND 5 more from BRAINLIEST.

posledela

3rd one from (left to right)

8 0

3 years ago

Sudha earns ` 189 in a day and Radha earns ` 112 in a day. About how much will each of them earn in 30 days

Mariulka [41]

Answer:

the sudha and radha earns 5,670 and 3,360 respectively

Step-by-step explanation:

Since in the question it is mentioned that

Sudha earns 189 in a day

And, radha earns 112 in a day

so in 30 days, sudha earns

= 189 × 30 days

= 5,670

And, radha earns

= 112 × 30 days

= 3,360

Therefore the sudha and radha earns 5,670 and 3,360 respectively

8 0

3 years ago

Verify a(b-c)=ab-ac for a=1.6;b=1/-2;& c=-5/-7

harina [27]

Given:

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

To verify:

$a(b-c)=ab-ac$ for the given values.

Solution:

We have,

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

We need to verify $a(b-c)=ab-ac$ .

Taking left hand side, we get

$a(b-c)=1.6\left(\dfrac{1}{-2}-\dfrac{-5}{-7}\right)$

$a(b-c)=1.6\left(-\dfrac{1}{2}-\dfrac{5}{7}\right)$

Taking LCM, we get

$a(b-c)=1.6\left(\dfrac{-7-10}{14}\right)$

$a(b-c)=\dfrac{16}{10}\left(\dfrac{-17}{14}\right)$

$a(b-c)=\dfrac{8}{5}\left(\dfrac{-17}{14}\right)$

$a(b-c)=-\dfrac{68}{35}\right)$

Taking right hand side, we get

$ab-ac=1.6\times \dfrac{1}{-2}-1.6\times \dfrac{-5}{-7}$

$ab-ac=-\dfrac{16}{20}-\dfrac{8}{7}$

$ab-ac=-\dfrac{4}{5}-\dfrac{8}{7}$

Taking LCM, we get

$ab-ac=\dfrac{-28-40}{35}$

$ab-ac=\dfrac{-68}{35}$

Now,

$LHS=RHS$

Hence proved.

7 0

3 years ago

What is the ratio of drivers to cars in a stock car race?

adoni [48]

It would be a 1-1 ration because there is 1 driver for every stock car

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3 years ago