Answer:
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Answer:
The resistivity of aluminum is 2.8 × 10–8m. What is the conductivity of aluminum? (2 points) Resistivity = 1 / conductivityx = 1/ 2.8 x 10^-8Resistivity= 36714285.71 Ohms 2.
I believe the answer to this is A.
Answer:
V2 = 90.7 mL
Explanation:
pressure and volume are inversely proportional, if the pressure is increased, the volume will decrease. In an isothermal process:
p1V1 = p2V2
V2 = p1V1/p2 = (277 torr×187 mL)/571 torr
V2 = 90.7 mL
