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sveta [45]
3 years ago
10

Calculate the kinetic energy, in J/mole, of 1.00 mole of gaseous water molecules at room temperature (25.0ºC).

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer: 23158.7J/mol

Explanation: Kinetic energy is the energy possessed by a body by virtue of its motion.

K.E=\frac{3}{2}\times {RT}

R= gas constant= 8.314 J/Kmol

T= temperature in Kelvin = 25 ° C = 25° C+273= 298 K

K.E=\frac{3}{2}\times {8.314J/Kmol\times 298K}

K.E = 23158.7 J

n= no of moles = 1 mole

Thu K.E per mole will be= 23158.7 J/mol




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<em />

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7.48mL = 7.48x10⁻³L ₓ (0.0250moles / L) = 1.87x10⁻⁴ moles of Ba²⁺ = Moles of SO₄²⁻

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