Question

Calculate the kinetic energy, in J/mole, of 1.00 mole of gaseous water molecules at room temperature (25.0ºC).

Answer 1

Answer: 23158.7J/mol

Explanation: Kinetic energy is the energy possessed by a body by virtue of its motion.

$K.E=\frac{3}{2}\times {RT}$

R= gas constant= 8.314 J/Kmol

T= temperature in Kelvin = 25 ° C = 25° C+273= 298 K

$K.E=\frac{3}{2}\times {8.314J/Kmol\times 298K}$

K.E = 23158.7 J

n= no of moles = 1 mole

Thu K.E per mole will be= 23158.7 J/mol