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2 years ago

Calculate the kinetic energy, in J/mole, of 1.00 mole of gaseous water molecules at room temperature (25.0ºC).

Chemistry

1 answer:

soldi70 [24.7K]2 years ago

8 0

Answer: 23158.7J/mol

Explanation: Kinetic energy is the energy possessed by a body by virtue of its motion.

$K.E=\frac{3}{2}\times {RT}$

R= gas constant= 8.314 J/Kmol

T= temperature in Kelvin = 25 ° C = 25° C+273= 298 K

$K.E=\frac{3}{2}\times {8.314J/Kmol\times 298K}$

K.E = 23158.7 J

n= no of moles = 1 mole

Thu K.E per mole will be= 23158.7 J/mol

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According to the following reaction, how many moles of oxygen gas are necessary to form 0.408 moles carbon dioxide?

Neporo4naja [7]

Answer:

2 molecules of oxygen are necessary

3 0

1 year ago

Consider the aldol condensation between dibenzyl ketone and benzil in strong base. Calculate the molar masses of the reactants a

Sati [7]

Answer:

a) 210.3 g/mol

b) 210.2 g/mol

c) 384.5 g/mol

Explanation:

First step we will calculate the molar masses of ; carbon atom, hydrogen atom and oxygen atom in each .

Molar mass of dibenzyl ketone

Molar mass of dibenzyl ketone = ∑ molar masses of atoms in dibenzyl ketone

= carbon( 15 ) = 15 ( 12.0107 ) + oxygen ( 14 ) = 1 ( 15.999 ) + hydrogen(14) =14(1.00784)

= 210.26926 ≈ 210.3 g/mol

Molar mass of benzil

Molar mass of Benzil = ∑ molar masses of atoms in Benzil

= carbon( 14) = 14(12.0107) + oxygen(2) = 2 ( 15.999) + hydrogen(10) =10(1.00784)

= 210.2262 ≈ 210.2 g/mol

Molar mass of 2,3,4,5-tetraphenylcyclopentadienone

Molar mass = ∑ molar masses of atoms

= carbon ( 29) = 29(12.0107) + oxygen (1) = 1( 15.999 ) + hydrogen(20) = 20(1.00784 )

≈ 384.5 g/mol

6 0

2 years ago

When considering free energy change, biochemists usually define a standard state, the biochemical standard state, which is modif

kodGreya [7K]

Answer:

The conditions for biochemical, chemical and both standard states are shown below

Explanation:

Chemical standard state:

Temperature is 25°

Intial concntration of reactants and products is 1M

g. Presurre is 1 atm.

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Biochemical standard state:

Temperature is 25°

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Constant value of Mg2+

Both:

Intial concntration of reactants and products is 1M

g. Presurre is 1 atm.

Temperature is 25°

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7 0

2 years ago

2.24g of iron combine with 0.96g of oxygen to form an oxide of iron. Determine the formula of this oxide of iron and use it to c

irakobra [83]

Answer:

See Explanation

Explanation:

Let us find the number of moles of each element

For iron = 2.24g/56 = 0.04 moles

For oxygen = 0.96 g/16 = 0.06 moles

Then we divide by the lowest ratio;

0.04/0.04 and 0.06/0.04

1 and 2

We Thus obtain 1 : 1.5

Multiplying through by 2 we have; 2 : 3

The formula of the oxide formed is Fe2O3

The balanced equation is;

4Fe + 3O2 ------> 2Fe2O3

6 0

2 years ago

A sample of neon gas has a volume of 752 mL at 298 Kelvin (K). What will be the volume at 373 K if

Firdavs [7]

Answer:

V2 = 0.941 L

Explanation:

This follows the Charles' law, a gas law.

Using this eq $\frac{V1}{T1} =\frac{V2}{T2}$

From the given, the missing variable is V2

$\frac{752 ml}{298 K} =\frac{V2}{373 K}$ , change ml to SI unit of Volume (L)

752 ml = 0.752 L

$\frac{752 L}{298 K} =\frac{V2}{373 K}$ , then cross multiply

$280.496 L (K) =298K (V2)$

$\frac{280.496 L (K) }{298K} = (V2)$

$V2 = 0.941 L$

8 0

2 years ago