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sveta [45]
3 years ago
10

Calculate the kinetic energy, in J/mole, of 1.00 mole of gaseous water molecules at room temperature (25.0ºC).

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer: 23158.7J/mol

Explanation: Kinetic energy is the energy possessed by a body by virtue of its motion.

K.E=\frac{3}{2}\times {RT}

R= gas constant= 8.314 J/Kmol

T= temperature in Kelvin = 25 ° C = 25° C+273= 298 K

K.E=\frac{3}{2}\times {8.314J/Kmol\times 298K}

K.E = 23158.7 J

n= no of moles = 1 mole

Thu K.E per mole will be= 23158.7 J/mol




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3 years ago
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1.1 mol

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8 0
2 years ago
2. Extract the relevant information from the question: NaOH V = 30 mL , M = 0.10 M HCl V = 25.0 mL, M = ?
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Answer:

0.12M

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A balanced equation for the reaction will go a great deal in obtaining our desired result. So, let us write a balanced equation for the reaction

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use the equation 2C4H10 +13O2-->8CO2+10H2O to find how many moles of oxygen would react with .425 mol C4H10
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2C4H10 + 13O2  →  8CO2 + 10H2O Since the equation is balanced, we can set up a proportion: 13 moles of O2 react with 2 moles of C4H10x  moles of O2 react with 0.425 moles of C4H10 13 → 2x → 0.425 x = 13 * 0.425 / 2 = 2.7625 <span>2.7625 moles of O2 react with 0.425 moles of C4H10</span> 
6 0
3 years ago
Read 2 more answers
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