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sveta [45]
3 years ago
10

Calculate the kinetic energy, in J/mole, of 1.00 mole of gaseous water molecules at room temperature (25.0ºC).

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer: 23158.7J/mol

Explanation: Kinetic energy is the energy possessed by a body by virtue of its motion.

K.E=\frac{3}{2}\times {RT}

R= gas constant= 8.314 J/Kmol

T= temperature in Kelvin = 25 ° C = 25° C+273= 298 K

K.E=\frac{3}{2}\times {8.314J/Kmol\times 298K}

K.E = 23158.7 J

n= no of moles = 1 mole

Thu K.E per mole will be= 23158.7 J/mol




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Brut [27]
Missing in your question :

Ksp of(CaCO3)= 4.5 x 10 -9

Ka1 for (H2CO3) =  4.7 x 10^-7

Ka2 for (H2CO3) = 5.6 x 10 ^-11

1) equation 1 for Ksp = 4.5 x 10^-9 

CaCO3(s)→ Ca +2(aq)    +  CO3-2(aq)  

2) equation 2 for Ka1 = 4.7 x 10^-7

 H2CO3 + H2O → HCO3- + H3O+

3) equation 3 for Ka2 = 5.6 x 10^-11

 HCO3-(aq) + H2O(l) → CO3-2 (aq)  + H3O+(aq)

so, form equation 1& 2&3 we can get the overall equation:
CaCO3(s)  +  H+(aq)  → Ca2+(aq)   + HCO3-(aq)

note: you could get the overall equation by adding equation 1 to the inverse of equation 3 as the following:
when the inverse of equation 3 is :

CO3-2 (aq) + H3O+ (aq) ↔ HCO3- (aq) + H2O(l)  Ka2^-1 = 1.79 x 10^10
when we add it to equation 1
CaCO3(s) ↔ Ca2+(aq)  +  CO3-2(aq)   Ksp = 4.5 x 10^-9

∴ the overall equation will be as we have mentioned before:
when H3O+ = H+

CaCO3(s) + H+(aq)  ↔ Ca2+ (aq) + HCO3-(aq)   K= 80.55

from the overall equation:

∴K = [Ca2+][HCO3-] / [H+]

when we have [Ca2+] = [HCO3-] so we can assume both = X

∴K = X^2 / [H+]

when we have the PH = 5.6 so we can get [H+]

PH = - ㏒[H+]
5.6 = -㏒[H]
∴[H] = 2.5 x 10^-6

so, by substitution on K expression:

∴ 80.55 = X^2 / (2.5 x10^-6)

∴X = 0.0142

∴[Ca2+] = X = 0.0142 
6 0
3 years ago
A chemical equation is balanced by what
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Answer:

adding coefficient

Explanation:

To balance a chemical equation we have to place coefficients as needed in front of the symbols or formulas so the same number of each type of atom occurs in both reactants and products

7 0
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It is composed of coal and is produced by incomplete combustion of coal, oil wood, or other fuels
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HELLPPPPP 5th grade math
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Energy inputs, outputs and losses are summarized below:

  1. Input - Chemical energy/Output - Luminous energy/Losses - Hystheresis-related dissipation.
  2. Input - Fluid energy, heat/Output - Translational mechanical energy/Losses - Waste energy.
  3. Input - Translational mechanical energy/Output - Rotational mechanical energy/Losses - Friction-related work.
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  5. Input - Translational and rotational mechanical energy/Output - Translational mechanical energy/Losses - Friction-related work, drag-related work.
  6. Input - Fluid energy, heat/Output - Translational and rotational mechanical energy/Losses - Waste energy, friction-related work and drag-related work.

<h2>Procedure - Application of the principle of energy conservation</h2><h2 /><h3>Introduction</h3><h3 />

In this question we must apply the definition of the principle of energy conservation to each case, understanding what kind of <em>energy</em> inputs (E_{in}) and outputs exists (E_{out}, E_{loss}).

We proceed to apply a simplified scheme, on the assumption that each system works at <em>steady</em> state, in which we shall construct each answer:

E_{in} - E_{out} - E_{l} = 0 (1)

Where:

  • E_{in} - Energy input.
  • E_{out} - Energy output.
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<h3>Case analysis</h3>

Now we proceed to summarize the inputs, outputs and losses for each case:

<h3><em>Flashlight</em></h3>

Input - Chemical energy (battery)/Output - Luminous energy (screen)/Losses - Hystheresis-related dissipation (battery)

<h3><em>Hot air balloon</em></h3>

Input - Fluid energy (fuel), heat (ignition)/Output - Translational mechanical energy (Buoyancy force)/Losses - Waste energy (smog)

<h3><em>Water wheel</em></h3>

Input - Translational mechanical energy (water flow)/Output - Rotational mechanical energy (wheel)/Losses - Friction-related work (bearings, etc)

<h3><em>Fan</em></h3>

Input - Electric energy (current)/Output - Translational and rotational mechanical energy  (wind)/Losses - Power dissipation (AC engine/cables), drag-related work (interaction between air and fan)

<h3><em>Hitting a golf ball</em></h3>

Input - Translational and rotational mechanical energy (arm)/Output - Translational mechanical energy (ball)/Losses - Friction-related work (Human body, interactions between player and ball), drag-related work (interactions between ball and air)

<h3><em>Motorcycle</em></h3>

<em></em>

Input - Fluid energy (fuel), heat (ignition)/Output - Translational and rotational mechanical energy (motorcycle and driver)/Losses - Waste energy (smog), friction-related work (interaction between tires and ground) and drag-related work (interactions between driver, motorcycle and surrounding air)

To learn more on energy conversion, we kindly invite to check this verified question: brainly.com/question/11234965

5 0
2 years ago
The commands given in nucleus are throughout the cell by the
qwelly [4]

Answer:

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The endoplamic reticulum  is an important organelle in protein synthesis. The nucleus contains DNA, which is the template for transcription of mRNA. mRNA acts as a message, which leaves the nucleus to become translated into proteins.

The endoplasmic reticulum is important in the synthesis, folding, and modification of proteins.  

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