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Aleks04 [339]
3 years ago
8

Name the cycloalkanes with molecular formula c6h12 that have a 3-membered ring and two substituents.

Chemistry
1 answer:
Tanzania [10]3 years ago
3 0

Answer:

1-ethyl-2-methyl cyclopropane.

Explanation:

  • The structure of the molecule will be as shown in the attached image.
  • The molecular formula of the compound is C₆H₁₂.
  • It has 3 membered ring with 3 C atoms and two substituents one of them with one C atom (methyl) and the other with 2 C atoms (ethyl).
  • The ring consist of 3 C atoms, so its name is cyclo propane.
  • We numbering the atoms of the ring that give the ethyl substituent the low no. (1) and then methyl group take no. (2).
  • <em>Thus, the name of the compound is 1-ethyl-2-methyl cyclopropane.</em>

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Do a quick conversion: 1 grams Co2 = 0.0084841820909097 mole using the molecular weight calculator and the molar mass of Co2.

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Are substances that taste bitter and feel slippery to the skin
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Answer:

Explanation:

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3 years ago
The conversion of methyl isonitrile to acetonitrile in the gas phase at 250 °C CH3CN(g) is first order in CH3NC with a rate cons
nadya68 [22]

Answer: The concentration of CH_3NC will be 1.56\times 10^{-2}M after 416 seconds have passed.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant = 3.00\times 10^{-3}s^{-1}

t = age of sample = ?

a = let initial amount of the reactant = 5.45\times 10^{-2}M

a - x = amount left after decay process = 1.56\times 10^{-2}M

t=\frac{2.303}{3.00\times 10^{-3}}\log\frac{5.45\times 10^{-2}}{1.56\times 10^{-2}}

t=416s

The concentration of CH_3NC will be 1.56\times 10^{-2}M after 416 seconds have passed.

5 0
3 years ago
Heating 2.40 g of the oxide of metal X (molar mass of X = 55.9 g/mol) in carbon monoxide (CO) yields the pure metal and carbon d
Korolek [52]

Answer:The molecular formula of the oxide of metal be X_2O_3. The balanced equation for the reaction is given by:

X_2O_3+3CO\rightarrow 3CO_2+2X

Explanation:

Let the molecular formula of the oxide of metal be X_2O_y

X_2O_y+yCO\rightarrrow yCO_2+2X

Mass of metal product = 1.68 g

Moles of metal X =\frac{1.68 g}{55.9 g/mol}=0.03005 mol

1 mol of metal oxide produces 2 moles of metal X.

Then 0.03005 moles of metal X will be produced by:

\frac{1}{2}\times 0.03005 mol=0.01502 mol of metal oxide

Mass of 0.01502 mol of metal oxide = 2.40 g (given)

0.01502 mol\times (2\times 55.9 g/mol+y\times 16 g/mol)=2.40 g

y = 2.999 ≈ 3

The molecular formula of the oxide of metal be X_2O_3. The balanced equation for the reaction is given by:

X_2O_3+3CO\rightarrow 3CO_2+2X

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