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3 years ago

Name the cycloalkanes with molecular formula c6h12 that have a 3-membered ring and two substituents.

Chemistry

1 answer:

Tanzania [10]3 years ago

3 0

Answer:

1-ethyl-2-methyl cyclopropane.

Explanation:

The structure of the molecule will be as shown in the attached image.

The molecular formula of the compound is C₆H₁₂.

It has 3 membered ring with 3 C atoms and two substituents one of them with one C atom (methyl) and the other with 2 C atoms (ethyl).

The ring consist of 3 C atoms, so its name is cyclo propane.

We numbering the atoms of the ring that give the ethyl substituent the low no. (1) and then methyl group take no. (2).

<em>Thus, the name of the compound is 1-ethyl-2-methyl cyclopropane.</em>

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What are the oxidation numbers for groups 1-18 (skip groups 3-12)

Brilliant_brown [7]

Group 1: +1
Group 2: +2
Group 13: +3
Group 14: +4
Group 15: -3
Group 16: +II
Group 17: -1

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2 years ago

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Write a balanced chemical equation describing the oxidation of the bromide ion by solid xenon trioxide to produce bromine liquid

ki77a [65]

Answer:

6Br⁻ + XeO₃ + 6H⁺ → 3Br₂ + Xe + 3H₂O

Explanation:

First, we need to write the half-reactions:

2Br⁻ → Br₂ + 2e⁻ Oxidation -Balanced yet-

XeO₃ → Xe Reduction

To balance the reduction in acidic aqueous solution we need to add waters in the other side of the reaction as oxygens are present:

XeO₃ → Xe + 3H₂O

And H⁺ as hydrogens from water we have:

XeO₃ + 6H⁺ → Xe + 3H₂O

To balance the charge:

<h3>XeO₃ + 6H⁺ + 6e⁻ → Xe + 3H₂O Reduction -Balanced-</h3><h3 />

To cancel out the electrons of both half-reaction we need to multiply oxidation 3 times:

6Br⁻ → 3Br₂ + 6e⁻

XeO₃ + 6H⁺ + 6e⁻ → Xe + 3H₂O

And the balanced reaction in acidic aqueous solution is the sum of both half-reactions:

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2 years ago

The analogy that forms the basis of the octet rule compares covalent valence

o-na [289]

Answer:

Explanation:

orbital overlap electron densities.

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3 years ago

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A mixture that results when substances dissolve to form a homogeneous mixture

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A mixture that results when substances dissolve to form a homogeneous mixture is a solution.

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3 years ago

How many hydrogen atoms are in 35.0 grams of hydrogen gas? How many hydrogen atoms are in 35.0 grams of hydrogen gas? 4.25 × 102

Ede4ka [16]

Answer: $2.12\times 10^{25}$ atoms of hydrogen are there in

35.0 grams of hydrogen gas.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{35.0g}{2g/mol}=17.5moles$

1 mole of hydrogen $(H_2)$ = $2\times 6.023\times 10^{23}=12.05\times 10^{23}$ atoms

17.5 mole of hydrogen $(H_2)$ = $\frac{12.05\times 10^{23}}{1}\times 17.5=2.12\times 10^{25}$ atoms

There are $2.12\times 10^{25}$ atoms of hydrogen are there in

35.0 grams of hydrogen gas.

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3 years ago