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Aleks04 [339]
3 years ago
8

Name the cycloalkanes with molecular formula c6h12 that have a 3-membered ring and two substituents.

Chemistry
1 answer:
Tanzania [10]3 years ago
3 0

Answer:

1-ethyl-2-methyl cyclopropane.

Explanation:

  • The structure of the molecule will be as shown in the attached image.
  • The molecular formula of the compound is C₆H₁₂.
  • It has 3 membered ring with 3 C atoms and two substituents one of them with one C atom (methyl) and the other with 2 C atoms (ethyl).
  • The ring consist of 3 C atoms, so its name is cyclo propane.
  • We numbering the atoms of the ring that give the ethyl substituent the low no. (1) and then methyl group take no. (2).
  • <em>Thus, the name of the compound is 1-ethyl-2-methyl cyclopropane.</em>

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Answer:

Option C = 4.25 g

Explanation:

Ounce and grams are unit of mass. Ounce is larger unit while gram is smaller unit. The one ounce is consist of 28.35 g or we can say that one ounce is equal to 28.35 g. In order to convert the given ounce value into grams the value is multiply with 28.35 g.

Given data:

Mass = 0.15 ounce

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Solution:

One ounce is equal to 28.35 g, so

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matrenka [14]

Answer:

Average density of the liquid = 0.992 g/mL

Explanation:

Density = mass/volume

mass of liquid = (mass of liquid + mass of cylinder) - mass of cylinder

Trial 1: mass of liquid = 19.731 - 9.861 = 9.87

volume of liquid = 10 mL

density of liquid = 9.87 g / 10 mL = 0.987 g/mL

Trial 2: mass of liquid = 19.831 - 9.861 = 9.97

volume of liquid = 10 mL

density of liquid = 9.97 g / 10 mL = 0.997 g/mL

Trial 3: mass of liquid = 19.831 - 9.861 = 9.97

volume of liquid = 10 mL

density of liquid = 9.97 g / 10 mL = 0.997 g/mL

Trial 4: mass of liquid = 19.771 - 9.861 = 9.91

volume of liquid = 10 mL

density of liquid = 9.91 g / 10 mL = 0.991 g/mL

Trial 5: mass of liquid = 19.751 - 9.861 = 9.89

volume of liquid = 10 mL

density of liquid = 9.89 g / 10 mL = 0.989 g/mL

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Average density of the liquid = 0.992 g/mL

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3 years ago
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