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devlian [24]
3 years ago
5

A rifle of mass M is initially at rest, but is free to recoil. It fires a bullet of mass m with a velocity +v relative to the gr

ound.After the rifle is fired, its velocity relative to the ground is??m/Mv.?mv/(M+m).?mv/M.?v.
Physics
1 answer:
Natali5045456 [20]3 years ago
6 0

Answer:

V=-\dfrac{mv}{M}

Explanation:

Given that

Mass of rifle = M

Initial velocity ,u= 0

Mass of bullet = m

velocity of bullet =  v

Lets take final speed of the rifle is V

There is no any external force ,that is why linear momentum of the system will be conserve.

Initial linear momentum = Final  linear momentum

 M x 0 + m x 0 = M x V + m v

0 =  M x V + m v

V=-\dfrac{mv}{M}

Negative sign indicates that ,the recoil velocity will be opposite to the direction of bullet velocity.

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