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2 years ago

What can be defined as the rate at which velocity changes

Physics

2 answers:

siniylev [52]2 years ago

8 0

The rate at which velocity changes can be defined as acceleration or average acceleration.

<u>Explanation:</u>

The acceleration is defined as the rate of change of velocity with respect to time. So, the change in velocity from the initial velocity at different time intervals will help to attain the acceleration attained by the object.

$\ a =\frac{v_{f}-v_{i}}{\Delta t}$

where,

$v_{f} \text { and } v_{i}$ – final and initial velocities, $\Delta t$ – time

If the change in velocity is constant for same time interval, then the acceleration will be constant for that object. So, an object can attain uniform acceleration when the velocity changes uniformly with time.

taurus [48]2 years ago

4 0

Answer:

acceleration

Explanation:

The rate at which velocity changes is the definition of the physical quantity called acceleration, and it is given by the formula: $a=\frac{v_f-v_i}{\Delta t}$

where $\Delta t$ is the time that took to change from the initial velocity $v_i$ to the final velocity $v_f$

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What does the path of an object look like when it is in uniform motion?

marysya [2.9K]

Answer:

The path of an object in uniform motion is a straight line.

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1 year ago

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Is a solid...
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3 years ago

A skater of mass 60 kg has an initial velocity of 12 m/s. He slides on ice where the frictional force is 36 N. How far will the

Alexus [3.1K]

Answer:

d = 120 [m]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. Where the energy in the final state (when the skater stops) is equal to the sum of the mechanical energy in the initial state plus the work done on the skater in the initial state.

The mechanical energy is equal to the sum of the potential energy plus the kinetic energy. As the track is horizontal there is no unevenness, in this way, there is no potential energy.

E₁ + W₁₋₂ = E₂

where:

E₁ = mechanical energy in the initial state [J] (units of Joules)

W₁₋₂ = work done between the states 1 and 2 [J]

E₂ = mechanical energy in the final state = 0

E₁ = Ek = kinetic energy [J]

E₁ = 0.5*m*v²

where:

m = mass = 60 [kg]

v = initial velocity = 12 [m/s]

Now, the work done is given by the product of the friction force by the distance. In this case, the work is negative because the friction force is acting in opposite direction to the movement of the skater.

W₁₋₂ = -f*d

where:

f = friction force = 36 [N]

d = distance [m]

Now we have:

0.5*m*v² - (f*d) = 0

0.5*60*(12)² - (36*d) = 0

4320 = 36*d

d = 120 [m]

7 0

2 years ago

The width of the central maximum is defined as the distance between the two minima closest to the center of the diffraction patt

Gnom [1K]

Answer:

The value of the angle is $\bf{ \sin^{-1}[h/am_{e}v]}$ .

Explanation:

Given:

The condition for diffraction minima is

$a \sin \theta = m \lambda~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)$

where, $a$ is the slit-width, $\theta$ is the angle of incidence, $m$ is the order number and $\lambda$ is the wavelength of the light.

The wavelength of an electron traveling through a medium is governed by de Broglie's hypothesis.

According to de Broglie's hypothesis

$\lambda &=& \dfrac{h}{p}\\ &=& \dfrac{h}{m_{e}v}$

Here, $h$ is Planck's constant, $m_{e}$ is the mass of the electron and $v$ is the velocity of the electron.

For first minimum $m = 1$ .

From equation (1), we have

$&& a \sin \theta = \dfrac{h}{m_{e}v}\\&or,& \theta = \sin^{-1}[\dfrac{h}{am_{e}v}]$

6 0

3 years ago

If light is used to promote the electron, what are the selection rules for the initial and final spin and orbital angular moment

loris [4]

Answer:

(1) $\Delta S=0$

(2) $\Delta L=0, +1,-1$ but $J=0 to J=0$ transition not allowed.

Explanation:

Atoms can be described by the quantum number n, spin quantum number S, angular momentum quantum number L, and total angular momentum quantum number J. Based on approximation Russel- Saunders electron coupling, the atomic term symbol can be written as $L_{J} ^{2S+1}$ .

The conditions or selection rule to promoting the electron are discussed below:

(1) The total spin should not change that is $\Delta S=0$ .

(2) The total angular momentum change should be, $\Delta L=0, +1,-1$ but $J=0 to J=0$ transition not allowed.

8 0

3 years ago