The answer is C.
Alpha particles are simply helium-4 nuclei, with 2 protons and 2 neutrons. Charge is 2+, and mass is on the order of 4amu. Beta particles are either electrons or positrons, with charges of 1- and 1+ respectively. Their masses are fractions of amu, so alpha particles and beta particles differ in both mass and charge.
Answer:
The amount of HC₂H3₃2(aq) in the flask after the addition of 5.0mL of NaOH(aq) compared to the amount of HC₂H₃O₂(aq) in the flask after the addition of 1.0mL is much smaller because more HC₂H₃O₂(aq) is required to react with 5.0 mL NaOH than with 1.0 mL NaOH.
Explanation:
Equation of the reaction between acetic acid, HC₂H₃O₂(aq) and sodium hydroxide, NaOH(aq) is given below:
CH₃COOH (aq) + NaOH (aq) ----> CH₃COONa (aq) + H₂O
The equation of the reaction shows that acetic acid andsodium hydroxide will react in a 1:1 ratio
Since the concentration of NaOH was not given, we can assume that the concentration is 0.01 M
Moles of NaOH in 5.0 mL of 0.01 M NaOH = 0.01 × 5/1000 = 0.00005 moles
Moles of NaOH in 1.0 mL of 0.01 M NaOH = 0.01 ×1/1000 = 0.0001 moles
Ratio of moles of NaOH in 5.0 mL to 1.0 mL = 0.00005/0.00001 = 5
There are five times more moles of NaOH in 5.0 mL than in 1.0 mL and this means that 5 times more the quantity of HC₂H₃O2(aq) required to react with 1.0 mL NaoH is needed to react with 5.0 mL NaOH.
Therefore, the amount of HC₂H₃O2(aq) in the flask after the addition of 5.0mL of NaOH(aq) compared to the amount of HC₂H₃O₂(aq) in the flask after the addition of 1.0mL is much smaller because more HC₂H₃O₂(aq) is required to react with 5.0 mL NaOH than with 1.0 mL NaOH.
Answer:
41.66 mL of 12.0 M sulfuric acid are needed.
Explanation:
Concentration of sulfuric acid solution taken =
Volume of the 12.0 M Solution = 
Concentration of required solution = 
Volume of required 1.00 M solution = 
(Dilution)
41.66 mL of 12.0 M sulfuric acid are needed.
The freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it decrease and increase respectively.
Sorry I’m only answering so I could upload
Answer:
Reactants: K = 2, S = 1, Co = 1, Cl = 2; Products: K = 2, S = 1, Co = 1, Cl = 2
Explanation:
The reaction is a double replacement reaction so the anions (Cl⁻ and S²⁻) switch places.
<u>1</u> K₂S + <u>1</u> CoCl₂ ⇒ <u>2</u> KCl + <u>1 </u>CoS (balanced chemical equation)
On the reactants and products side, K = 2, S = 1, Co = 1, and Cl = 2.
Hope that helps.
