I think this one is the organelles.
To ensure that the 9-Fluorenone was totally dry, it had to be washed with methylene chloride. To make sure that methylene chloride is present in a pure solution, sodium sulfate binds to water and precipitates.
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What is the purpose of the sodium sulfate?</h3>
- Although it has numerous additional uses, sodium sulfate is primarily employed in the production of detergents and in the Kraft process of paper pulping.
- The decahydrate's natural mineral form, mirabilite, accounts for about half of the world's output, with the other half coming from chemical byproducts. Sodium sulfate was used as a drying, isolating, and anhydrous salt for the 9-fluorenone.
- To make sure that methylene chloride is present in a pure solution, sodium sulfate binds to water and precipitates.
- The sodium salt of sulfuric acid is known as sodium sulfate. Na2SO4 is the chemical formula for sodium sulfate. The mineral thenardite, which is also known as anhydrous sulfate, is described as a white, crystalline solid, whereas the decahydrate Na2SO4. 10H2O is also known as Glauber's salt or the mirabilis salt.
To know more about sodium sulfate, refer:
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The birds could have more diseases and could pass it to other reptiles
Answer:
The answer to your question is: letter D
Explanation:
In a combustion reaction, the reactants are always a molecule with Carbon that reacts with oxygen and the products are carbon dioxide and water.
According to the explanation, the only possible solution is:
a) C₆H₁₂O₂(l) ⇒ 6 C(s) + 6 H₂(g) + O₂(g)
b) Mg(s) + C₆H₁₂O₂(l) ⇒ MgC₆H₁₂O₂(aq)
c) 6 C(s) + 6 H₂(g) + O₂(g) ⇒ C₆H₁₂O₂(l)
d) C₆H₁₂O₂(l) + 8 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(g)
e) None of the above represent the combustion of C₆H₁₂O₂.
Answer:
The answer is 6.25g.
Explanation:
First create your balanced equation. This will give you the stoich ratios needed to answer the question:
2C8H18 + 25O2 → 16CO2 + 18H2O
Remember, we need to work in terms of NUMBERS, but the question gives us MASS. Therefore the next step is to convert the mass of O2 into moles of O2 by dividing by the molar mass:
7.72 g / 16 g/mol = 0.482 mol
Now we can use the stoich ratio from the equation to determine how many moles of H2O are produced:
x mol H2O / 0.482 mol O2 = 18 H2O / 25 O2
x = 0.347 mol H2O
The question wants the mass of water, so convert moles back into mass by multiplying by the molar mass of water:
0.347 mol x 18 g/mol = 6.25g
