Answer:
<h2>
650W/m²</h2>
Explanation:
Intensity of the sunlight is expressed as I = Power/cross sectional area. It is measured in W/m²
Given parameters
Power rating = 6.50Watts
Cross sectional area = 100cm²
Before we calculate the intensity, we need to convert the area to m² first.
100cm² = 10cm * 10cm
SInce 100cm = 1m
10cm = (10/100)m
10cm = 0.1m
100cm² = 0.1m * 0.1m = 0.01m²
Area (in m²) = 0.01m²
Required
Intensity of the sunlight I
I = P/A
I = 6.5/0.01
I = 650W/m²
Hence, the intensity of the sunlight in W/m² is 650W/m²
Answer:
895522 times faster.
Explanation:
From the question given above, the following data were obtained:
Speed of sound in air (v) = 335 m/s
Speed of light in air (c) = 3×10⁸ m/s
How many times faster =.?
To obtain how many times faster light travels in air than sound, do the following
c : v => 3×10⁸ : 335
c/v = 3×10⁸ / 335
c/v = 895522
Cross multiply
c = 895522 × v
From the illustrations made above, we can see that the speed of the light in air (c) is 895522 times the speed of sound in air.
Thus, light travels 895522 times faster than sound in air.
The new period will be 2.486 days.
<h3>What is the period?</h3>
The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.
Given data;
Mass of a star,m= 1.210×10³¹ kg
The time period for one rotation of the star, T = 20.30 days
D' = 0.350 D
R' = 0.350 R
From the law of conservation of angular momentum;
Hence, the new period will be 2.486 days.
To learn more about the period, refer to the link;
brainly.com/question/569003
#SPJ1
<span>A joule is equal to one watt per second and so we must find out how many seconds are in two hours.
A shortcut you can use is remove the zeros and multiplying the remaining numbers before adding the the zeros back to the total of your result
6 x 6 x 2 = 72 and thus
60 x 60 x 2 = 7200
72 x 15 = 1080 and thus
7200 x 1500 = 10800000 joules
one mega joule equals one million joules
So we can simplify things and say 10.8 MJ</span>
Answer:
5.9 cm
Explanation:
We'll begin by calculating the spring constant (K) of the spring. This can be obtained as follow:
Force (F) = 15 N
Extention (e) = 3 cm
Spring constant (K) =.?
F = Ke
15 = K × 3
Divide both side by 3
K = 15 / 3
K = 5 N/cm
Therefore, the spring constant (K) is 5 N/cm.
Now, we shall determine how far the spring will stretch when a 3 kg candy is placed on the spring balance.
This can be obtained as follow:
First, we shall determine the weight of the object.
Mass of object = 3 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Weight (W) =?
W = mg
W = 3 × 9.8
W = 29.4 N
Finally, we shall determine how far the spring will stretch as follow:
Weight (W) = Force (F) = 29.4 N
Spring constant (K) = 5 N/cm
Extention (e) =?
F = ke
29.4 = 5 × e
Divide both side by 5
e = 29.4 / 5
e = 5.88 ≈ 5.9 cm
Therefore, the spring will stretch 5.9 cm when a 3 kg candy is placed on the spring balance.
