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satela [25.4K]
3 years ago
15

How do you suppose the frequency of an electromagnetic wave compares with the frequency of the electrons it sets into oscillatio

n in a receiving antenna?
Physics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

The frequencies are the same.

Explanation:

This is similar to the photoelectric effect. The frequency of the electromagnetic wave has to match a threshold frequency before it can set electrons into oscillation in a receiving antenna. After the frequency of the electromagnetic waves have matched and exceeded this threshold frequency, all of it's energy is converted to the kinetic energy of the electrons it sets into oscillation. And since their energies are similar, the frequencies too, subsequently, will be the same.

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Heat pumps move heat from __________ to __________ areas & REQUIRES energy. *
sergejj [24]
The correct answer to this question is false
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3 years ago
The children at the local park think the slide is too slow. There is too much fiction. What could you do to decrease the amount
igor_vitrenko [27]
In order to decrease the friction on the slide,
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-- Spray the whole slide with soapy sudsy water, every 30 minutes.

-- Drill a million holes in the slide,and pump high-pressure air
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-- Keep the slide very cold, and keep spraying it with a fine mist
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-- Ask a local auto mechanic to please, every time he changes
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-- Keep a thousand pairs of teflon pants near the bottom of the ladder
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7 0
4 years ago
The number of employees for a certain company has been decreasing each year by 4%. If the company currently has 650 employees an
nika2105 [10]
The answer would probably be 649.96
8 0
3 years ago
Glass is transparent to visibile light under normal conditions; however, at extremely high intensities, glass will absorb most o
8_murik_8 [283]

Answer:

3 photons

Explanation:

The energy of a photon E can be calculated using this formula:

E=\frac{hc}{\lambda}

Where h corresponds to Plank constant (6.626070x10^-34Js), c is the speed of light in the vacuum (299792458m/s) and \lambda is the wavelength of the photon(in this case 800nm).

E=\frac{hc}{\lambda}=\frac{(6.626070\times10^{-34})(299792458)}{800\times10^{-9}}=\frac{1.986445812\times10^-25}{800}=2.483057265\times10^{-19}J

Tranform the units

1eV=1.602176634\times10^{-19}J\\2.483057265\times10^{-19}J(\frac{1eV}{1.602176634\times10^{-19}J})=1.549802445eV

The band Gap is 4eV, divide the band gap between the energy of the photon:

\frac{4ev}{1.549802445eV}=2.508974118

Rounding to the next integrer: 3.

Three photons are the minimum to equal or exceed the band gap.

4 0
3 years ago
Which of the following is characteristic of proficient catching?
uysha [10]

Answer:

The correct answer is option D i.e. A and C

Explanation:

The correct answer is option D i.e. A and C

for proficient catching player must

- learn to absorbed the ball force

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- to catch ball at high height move the finger at higher position

- to catch ball at low height move the finger at lower position

5 0
3 years ago
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