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satela [25.4K]
3 years ago
15

How do you suppose the frequency of an electromagnetic wave compares with the frequency of the electrons it sets into oscillatio

n in a receiving antenna?
Physics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

The frequencies are the same.

Explanation:

This is similar to the photoelectric effect. The frequency of the electromagnetic wave has to match a threshold frequency before it can set electrons into oscillation in a receiving antenna. After the frequency of the electromagnetic waves have matched and exceeded this threshold frequency, all of it's energy is converted to the kinetic energy of the electrons it sets into oscillation. And since their energies are similar, the frequencies too, subsequently, will be the same.

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What is Potentiometer ​
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an instrument for measuring an electromotive force by balancing it against the potential difference produced by passing a known current through a known variable resistance.

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What is a nebula? <br> please help I am clueless
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4 0
3 years ago
Lightning a. occurs when a positively charged cloud base induces a negative charge on the Earth's surface. b. travels most often
mart [117]

Answer:

c. may be accompanied by the sound of explosively expanding hot air, called thunder.

Explanation:

Lightning is a discharge which is due to the reaction between oppositely charged charges in the clouds, or between clouds base and the Earth surface.

The motion of the cloud causes charging of clouds by friction, thus the reaction between opposite charges (jumping of charges from one cloud to another) in the cloud can lead to lightning. Also, oftentimes the bottom of a cloud is negatively charged so that this is attracted to the positive charge on the earth surface. Thus leading to a discharge called lightning.

Thus in the given question, the appropriate option is C. This implies that, lightning may be accompanied by the sound of explosively expanding hot air, called thunder.

8 0
3 years ago
Consider a venturi with a small hole drilled in the side of the throat. This hole is connected via a tube to a closed reservoir.
Marina CMI [18]

Answer:

(P_1-P_2)=1913.31 N/m^2

Explanation:

given:

\frac{A_t}{A_1}=0.85

V_1=90 m/s

γ∞=1.23 kg/m^3

solution:

since outside pressure is atm pressure vaccum can be defined by (P_1-P_2)

V_1=√2(P_1-P_2)/γ∞[\frac{A_t}{A_1}^2-1]

(P_1-P_2)=1913.31 N/m^2

6 0
3 years ago
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