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Kay [80]
3 years ago
13

Which material produces static charge when rubbed?

Physics
1 answer:
natita [175]3 years ago
5 0
Many materials produce static charge

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A paperboy rode his bike 3m/s. After being chased by a dog for 8 seconds he was traveling 6m/s. What is his accleration
aev [14]
I believe the answer is 0.375 m/s²
8 0
3 years ago
As a train accelerates uniformly, it passes successive 5-kilometer markers while traveling at velocities 10 m/s and 25 m/s. what
gregori [183]
<span>122.0 km/hr. First let’s make sure all of our units are in the base meter form: i.e. convert 5km to 5000m. (We will convert back to km later). The first thing to do is look at the equation relating velocity, acceleration, and distance: Vf^2 = Vi^2 + 2*a*d, where Vf is final velocity, Vi is initial velocity, a is acceleration, and d is distance. 25^2 = 10^2 + 2*a*5000 =?> 625 = 100 +10000a => a= 0.0525m/s^2. Now that we have acceleration, we can use the same equation again with different numbers.: Vf^2 = Vi^2 + 2*a*d = 25^2 + 2*0. 0525m*5000 = 625 + 525 =1150 => Vf^2 = 1150 => 33.9m/s. Convert to km/hour: 33.9m/s * 1km/1000m *60s/1min * 60min/ 1 hr = 122.0 km/hr.</span>
8 0
3 years ago
Whick type of macromolecule is made up of subnits that are called amino acids
crimeas [40]

The macromolecule that is made up of subunits that are called amino acids are the protein. The answer is therefore letter D. The carbohydrates are made up of subunits called monosaccarides. The lipids are mades up of subunits referred to as the fatty acid while nucleic acid are made up of nucleotides.

6 0
3 years ago
A steady 45 N horizontal force is applied to a 15 kg object a table. The object slides against a friction force of 30 N. Calcula
lisov135 [29]

The net force on an object subject to friction is equal to the sum of the applied force and the frictional force.

Mathematically,

F_{N} = ma = F_{applied} - f_{fr}

Here, m is mass of object and a is its acceleration. We take frictional force negative because it opposes the motion of object.

Given, m=15\ kg , F_{applied} =45\ N and f_{fr} = 30\ N

Substituting these values in above formula, we get

15\ kg\times a = 45\ N -30\ N=15\ N \\\\a=\frac{15\ N}{15\ kg} =1\ m/s^2.

Thus, the acceleration of an object is 1\ m/s^2.


6 0
3 years ago
Suppose a straight wire with a length of 2.0 m runs perpendicular to a magnetic field with a magnitude of 38 T. What current wou
iragen [17]

Answer:

9.67 A

Explanation:

The weight of a student with a mass of m = 75 kg is:

W=mg=(75 kg)(9.8 m/s^2)=735 N

where g=9.8 m/s^2 is the acceleration due to gravity.

We want the magnetic force on the wire to be equal to this weight. The magnetic force on the wire is

F=ILB sin \theta

where

I is the current in the wire

L = 2.0 m is the length of the wire

B = 38 T is the magnetic field

\theta=90^{\circ} is the angle between the direction of B and L

Since we want W=F, we can write

ILB sin \theta=W

And we can solve it to find the current I:

I=\frac{W}{BLsin\theta}=\frac{735 N}{(38 T)(2.0 m)(sin 90^{\circ})}=9.67 A

8 0
3 years ago
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