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3 years ago

Which are methods of reducing exposure to ionizing radiation? Check all that apply

Physics

2 answers:

Aloiza [94]3 years ago

7 0

Answer: a,d,e

Using a lead apron during medical X-rays

Using a short burst of X-rays to take an image

Taking an image of the smallest possible area

Explanation:

MariettaO [177]3 years ago

6 0

Ionising radiation (ionizing radiation) is radiation that carries enough energy to free electrons from atoms or molecules, thereby ionizing them. Ionizing radiation is made up of energetic subatomic particles, ions or atoms moving at high speeds (usually greater than 1% of the speed of light), and electromagnetic waves on the high-energy end of the electromagnetic spectrum.

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PLEASE HELP!!!!I IM GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (30pts)

maksim [4K]

Kinetic Energy

=>It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

Potential Energy 

=>potential energy is the energy held by an

 object because of its position relative to other

 objects, stresses within itself, its electric

 charge, or other factors.

<h2>Difference:</h2>

=>Potential energy is a stored energy on the other hand kinetic energy is the energy of an object or a system's particle in Motion.

6 0

3 years ago

1 poi

tatuchka [14]

Answer:

true

Explanation:

for example assume you are setting in a moving bus and when someone see you from the ground you are in motion but for some who is with you in the bus you are not in motion.

6 0

3 years ago

A 15 kg mass is moving at 7.50 meters per second on a horizontal, frictionless surface. What is the total work that must be done

sashaice [31]

Kinetic energy = (1/2) (mass) x (speed)²

At 7.5 m/s, the object's KE is (1/2) (7.5) (7.5)² = 210.9375 joules

At 11.5 m/s, the object's KE is (1/2) (7.5) (11.5)² = 495.9375 joules

The additional energy needed to speed the object up from 7.5 m/s
to 11.5 m/s is (495.9375 - 210.9375) = 285 joules.

That energy has to come from somewhere. Without friction, that's exactly
the amount of work that must be done to the object in order to raise its
speed by that much.

8 0

3 years ago

I would love to stretch a wire from our house to the Shop so I can 'call' my husband in for meals. The wire could be tightened t

dezoksy [38]

Note: I'm not sure what do you mean by "weight 0.05 kg/L". I assume it means the mass per unit of length, so it should be "0.05 kg/m".

Solution:
The fundamental frequency in a standing wave is given by
$f= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }$
where L is the length of the string, T the tension and m its mass. If we plug the data of the problem into the equation, we find
$f= \frac{1}{2 \cdot 24 m} \sqrt{ \frac{240 N}{0.05 kg/m} }=1.44 Hz$

The wavelength of the standing wave is instead twice the length of the string:
$\lambda=2 L= 2 \cdot 24 m=48 m$

So the speed of the wave is
$v=\lambda f = (48 m)(1.44 Hz)=69.1 m/s$

And the time the pulse takes to reach the shop is the distance covered divided by the speed:
$t= \frac{L}{v}= \frac{24 m}{69.1 m/s}=0.35 s$

7 0

4 years ago

The diver has least gravitational potentail engery at position

ankoles [38]

I'm not sure if a figure or some choices go along with this, but the closer to the sea floor the diver is, the lower the potential energy

7 0

3 years ago