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Aliun [14]
3 years ago
10

Which are methods of reducing exposure to ionizing radiation? Check all that apply

Physics
2 answers:
Aloiza [94]3 years ago
7 0

Answer: a,d,e

Using a lead apron during medical X-rays

Using a short burst of X-rays to take an image

Taking an image of the smallest possible area

Explanation:

MariettaO [177]3 years ago
6 0
Ionising radiation (ionizing radiation) is radiation that carries enough energy to free electrons from atoms or molecules, thereby ionizing them. Ionizing radiation is made up of energetic subatomic particles, ions or atoms moving at high speeds (usually greater than 1% of the speed of light), and electromagnetic waves on the high-energy end of the electromagnetic spectrum.
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Without completing the calculations, determine what the new volume will be in the problem below. Also, explain how you were able
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Boyles law

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Double the pressure equals 1/2 of original volume, assuming temperature remains the same.

So 40.0 mL is the new volume as it is compressed.
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. How does the area of a rectangle relate to the lengths of each side?
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What does aerobic refer to?
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Answer:

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Which of newton’s laws best explains why motorists should buckle up?
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Newton's first law of motion.
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3 years ago
A spherical balloon is made from a material whose mass is 3.30 kg. The thickness of the material is negligible compared to the 1
stellarik [79]

Answer:

563712.04903 Pa

Explanation:

m = Mass of material = 3.3 kg

r = Radius of sphere = 1.25 m

v = Volume of balloon = \frac{4}{3}\pi r^3

M = Molar mass of helium = 4.0026\times 10^{-3}\ kg/mol

\rho = Density of surrounding air = 1.19\ kg/m^3

R = Gas constant = 8.314 J/mol K

T = Temperature = 345 K

Weight of balloon + Weight of helium = Weight of air displaced

mg+m_{He}g=\rho vg\\\Rightarrow m_{He}=\rho vg-m\\\Rightarrow m_{He}=1.19\times \frac{4}{3}\pi 1.25^3-3.3\\\Rightarrow m_{He}=6.4356\ kg

Mass of helium is 6.4356 kg

Moles of helium

n=\frac{m}{M}\\\Rightarrow n=\frac{6.4356}{4.0026\times 10^{-3}}\\\Rightarrow n=1607.85489

Ideal gas law

P=\frac{nRT}{v}\\\Rightarrow P=\frac{1607.85489\times 8.314\times 345}{\frac{4}{3}\pi 1.25^3}\\\Rightarrow P=563712.04903\ Pa

The absolute pressure of the Helium gas is 563712.04903 Pa

3 0
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