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Ugo [173]
2 years ago
7

HELP 4 QUESTIONS PLEASE! (if you do all 4 ill pick u as brainliest and 100 pts) pictures below

Mathematics
1 answer:
myrzilka [38]2 years ago
6 0

{\large{\red{\mapsto{\maltese{\underline{\green{\boxed{\blue{\underbrace{\overbrace{\pink{\pmb{\bf{Answer:}}}}}}}}}}}}}}

1)

x + 42° + 46° = 180° (sum of all angles of triangle)

x + 88° = 180°

x = 180° - 88°

<u>x</u><u> </u><u>=</u><u> </u><u>9</u><u>2</u><u>°</u>

⠀

2)

x + 33° + 25° = 180° (sum of all angles of triangle)

x + 58° = 180°

x = 180° - 58°

<u>x</u><u> </u><u>=</u><u> </u><u>1</u><u>2</u><u>2</u><u>°</u>

⠀

3)

angle of beam = 90°

angle of wall = 75°

<u>angle between beam and wall = 90° - 75° = 15°</u>

⠀

4)

<u>complementary</u>

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Express this number in scientific notation: 22 cm.​
Tema [17]
2x 10^1 cm this will be the answer
5 0
3 years ago
What 1 thruogh 100 added up them divided
Marina CMI [18]
We can use the sum of an aritmetic sequence
the sum from n=1 to n=r when the first term is a1 and the nth term is an is
S=\frac{n(a_1+a_n)}{2}
first term is 1
last term is 100
there are 100 terms so n=100

so the sum is S=\frac{100(1+100)}{2}
S=(50)(101)
S=5050
now you want us to divide by 10
5050/10=505


fun fact, gauss (famous math guy) did this when he was younger, legend has it that he was assigned this as an in class assigment to kill time but gauss found a neat pattern, he noticed that adding the end terms wer giving the same sum, example, 100+1=101, 2+99=101, etc, so he just needed to find al the pairs and add them all up




answer is 505
the result is 505
5 0
3 years ago
Given f(x) =3x-7, find f(x+1)+f(1)
ELEN [110]

Answer:

3x - 8

Step-by-step explanation:

To find f(x + 1) substitute x = x + 1 into f(x)

f(x + 1) = 3(x + 1) - 7 = 3x + 3 - 7 = 3x - 4

Similarly

f(1) = 3(1) - 7 = 3 - 7 = - 4

Hence

f(x + 1) + f(1) = 3x - 4 - 4 = 3x - 8

3 0
3 years ago
State when the following equation will be true:<br> 36=9w hurry please
Ira Lisetskai [31]

Answer:

w=4

Step-by-step explanation:

4 0
3 years ago
Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur
Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle

for 0\le u\le7 and 0\le v\le\frac{2\pi}3, and a normal vector to this surface is

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle

with norm

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}

So the integral of f(x,y,z)=x^2+y^2+z^2 is

\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}

6 0
3 years ago
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