Question

What is the value of the discriminant of the quadratic equation -2^3=-8x+8

Answer 1

the value of the discriminant of the quadratic equation $-2x^2=-8x+8$  is $D =0$ .

Step-by-step explanation:

Here we need to find What is the value of the discriminant of the quadratic equation -2x^2=-8x+8 or , $-2x^2=-8x+8$ .

We know that for a quadratic equation , $f(x) = ax^2+bx+c$ , Discriminant is :

⇒ $D = b^2-4ac$

Now , let's frame equation $-2x^2=-8x+8$  in form of  $f(x) = ax^2+bx+c$  :

⇒ $-2x^2=-8x+8$

⇒ $2x^2-8x+8=0$

⇒ $x^2-4x+4=0$

Comparing values we get that here , a=1 , b = -4 , c = 4 . Putting these values in $D = b^2-4ac$ :

⇒ $D = (-4)^2-4(1)(4)$

⇒ $D =16-16$

⇒ $D =0$

Therefore , the value of the discriminant of the quadratic equation $-2x^2=-8x+8$  is $D =0$ .