What is the value of the discriminant of the quadratic equation -2^3=-8x+8

Mathematics

1 answer:

rjkz [21]3 years ago

7 0

the value of the discriminant of the quadratic equation $-2x^2=-8x+8$ is $D =0$ .

Step-by-step explanation:

Here we need to find What is the value of the discriminant of the quadratic equation -2x^2=-8x+8 or , $-2x^2=-8x+8$ .

We know that for a quadratic equation , $f(x) = ax^2+bx+c$ , Discriminant is :

⇒ $D = b^2-4ac$

Now , let's frame equation $-2x^2=-8x+8$ in form of $f(x) = ax^2+bx+c$ :

⇒ $-2x^2=-8x+8$

⇒ $2x^2-8x+8=0$

⇒ $x^2-4x+4=0$

Comparing values we get that here , a=1 , b = -4 , c = 4 . Putting these values in $D = b^2-4ac$ :

⇒ $D = (-4)^2-4(1)(4)$

⇒ $D =16-16$

⇒ $D =0$

Therefore , the value of the discriminant of the quadratic equation $-2x^2=-8x+8$ is $D =0$ .

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Please help me!

marusya05 [52]

Answer:

Step-by-step explanation:

Nice summary problem.

<AEC

AEC = 360 - 243.5 = 116.5
The number of degrees in 1 rotation of a circle = 360o. You have accounted for 243.5 degrees. What is left over is the answer.

<EAD and <ECD

Both of these are tangents to a circle. Tangents meet radii at 90 degree angles.

<EAD = <ECD = 90 degrees

<ABC

<ABC is 1/2 the central angle. The Central angle is <AEC

< AEC = 116.5
<ABC = 1/2 * 116.5
<ABC = 58.25

<ADC

There are 2 ways of doing this. You should know both of them.

One

All quadrilaterals = 360 degrees. You know three of the angles. You should be able to find ADC

<ADC + 90 + 90 + 116.5 = 360 Add the four angles together.
<ADC + 296.5 = 360 Combine terms on the left
<ADC = 360 - 296.5 Subtract 238.25 from both sides
<ADC = 63.5 Answer

Method Two

<ADC = 1/2 (major Arc - Minor Arc) This formula is fundamental to circle / tangent properties. The Major arc is the larger of the two parts of the circumference of a circle. The Minor arc is the smaller.