The correct answer is option B, 50%
Let us take the following case:
Genotype of heterozygous parent - (Aa)
Genotype of homozygous parent – (aa)
Allele I - (Aa)
Allele II – (aa)
The cross between the two is shown below:
Aa X aa
Aa, Aa, aa, aa
There are 50 % Aa, and 50 % aa allele.
Thus, the allele I (Aa) is 50 %.
Answer:
Hemophilia is a sex-linked recessive disorder in which a person's blood do not clots and he can bleed to death even after minor injuries because blood will keep running due to a small cut.
It is a recessive trait which means that even if one normal gene is present along with Hemophiliac gene, the person will not have the disease and he will be the carrier.
Question: What will be their children’s possible phenotypes?
If a woman who is a carrier for hemophilia marries a hemophiliac man, their genotypes can be denotes as :
Here H, indicate normal gene and small h indicate defected (hemophilia) gene.
Parents: XHXh X XhY
Offspring: XHXh : XHY: XhXh: XhY
Phenotype of offspring:
XHXh: The child will be daughter and normal (25 % chances)
XHY: The child will be son and normal (25 % chances)
XhXh: The child will be girl and Hemophiliac (25 % chances)
XhY: The child will be son and Hemophiliac (25 % chances)
Hope it helps!
Lysozyme which is found in the lysosomes. They function at a relatively low pH and are so because if they functioned at physiological pH they would digest the cell. But in this case, they are in the lysosomes where they are safe and at a lower pH so when the vesicles open they can emit hydrogen ions and the lysozyme to digest the foreign material.
