Answer:
In brief, electrons in the K⁺ ion occupy three main electron shells. In comparison, electrons in the Na⁺ ion occupy only two main electron shells.
Explanation:
Consider the electron cloud model for the structure of an atom or an ion. The nucleus was very dense and small. It was highly located at the center of the atom or the ion. Electrons occupy most of the space of the atom or ion.
If there are more than one electrons, they would be located in one or more main energy levels. Generally, for two atoms/ions with a similar number of protons, the one with more filled main electron shells would have a larger radius.
Electrons in a neutral Na atom occupy three main energy shells. The outermost shell contains only one electron. That electron would be removed first, such that in the Na⁺ ion, electrons would occupy only two main shells.
Similarly, electrons in a neutral K atom occupy four main energy shells. The outermost shell contains only one electron. That electron would be removed first, such that in the K⁺ ion, electrons would occupy three main shells.
Since there are more occupied electrons shells in K⁺ than in Na⁺, K⁺ would have a larger ionic radius.
Answer:
second carbon atom from the end
end carbon atom
Explanation:
Carbohydrates are naturally occurring organic compounds containing carbon, hydrogen and oxygen. The general molecular formula of Carbohydrates is .
Carbohydrates can be classified based on structures,
Carbohydrates with the structure of alkanals (-CHO) are known as aldose while those of the structure of alkanones (C=O) are known as ketose.
In stereochemistry , D series is a kind of configurational arrangement where the hydroxyl group attaches itself to the right hand side.
Thus; in naturally occurring D series of ketoses, the carbonyl group is found on carbon number <u>second carbon atom from the end </u>whereas in aldoses, the carbonyl group is found on carbon number <u> end carbon atom.</u>
Answer:
The longest wavelength is 2.19 × 10⁻⁷ m.
Explanation:
The work function (ф) is the minimum energy required to remove an electron from the surface of a metal. The minimum frequency required in a radiation to submit such energy can be calculated with the following expression.
ф = h × ν
where,
h is the Planck's constant (6.63 × 10⁻³⁴ J.s)
ν is the threshold frequency for the metal
In this case,
We can find the wavelength associated to this frequency using the following expression.
c = λ × ν
where,
c is the speed of light (3.00 × 10⁸ m/s)
λ is the wavelength
Then,