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xxTIMURxx [149]
2 years ago
12

In large generators in power plants, ___________ rotate inside a coil of wire to produce an electric current

Chemistry
1 answer:
lapo4ka [179]2 years ago
8 0
<h3><u>Answer;</u></h3>

Magnets

In large generators in power plants, <u>magnets</u> rotate inside a coil of wire to produce an electric current.

<h3><u>Explanation;</u></h3>
  • Generators are devices that use electromagnetic induction to convert mechanical energy to electrical energy.
  • In power plants, large wheel known as turbine that rotates when pushed by steam,wind, or water and provides mechanical energy to a generator.
  • <u><em>Generators are used in power plants and have very large quantities of copper wire spinning around inside very large magnets, at very high speeds. A turbine spins the shaft that runs the generator. Eventually, electric current is generated.</em></u>
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How many grams of NaCl (molecular weight = 58.4 g mole-1) would you dissolve in water to make a total volume of 500 mL of soluti
kolezko [41]

Given :

Volume , V = 500 mL .

Molarity , M = 0.5 M .

Molecular mass of NaCl is 58.4\ g/mole .

To Find :

How many grams of NaCl is required .

Solution :

Let , NaCl required is x gram .

Molarity is given by :

M=\dfrac{\text{Number of moles}}{\text{Volume (in liters) }}\\\\M=\dfrac{m}{M\times V}\\\\0.5=\dfrac{x}{58.4\times 0.5}\\\\x=0.5^2\times 58.4\ g\\\\x=14.6\ g

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6 0
2 years ago
In these chemical compounds, c is for carbon, o is for oxygen, n is for nitrogen, and k is for potassium. Which chemical compoun
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Answer:

carbon because organic compounds are made up of hydrogen and carbon

8 0
1 year ago
A sample of rubidium contains two different isotopes. 72.15% of the sample
Leona [35]

Answer:

Average atomic mass  = 85.557 amu.

Explanation:

Given data:

Percent abundance of Rb-85 = 72.15%

Percent abundance of Rb-87 = 27.85%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (72.15×85)+(27.85×87) /100

Average atomic mass =  6132.75 + 2422.95 / 100

Average atomic mass = 8555.7 / 100

Average atomic mass  = 85.557 amu.

4 0
2 years ago
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Sveta_85 [38]

Answer:

\large \boxed{\mathrm{subscripts}}

Explanation:

Subscripts are numbers written after elements, subscripts indicate how many of each atom there are in a compound.

8 0
3 years ago
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