Question

YOU GUYSS SHOULD HELPP ME WITH THISSS PLSSS I SHOULDD SUBMIT IT TOMORROW PLSSSSSSSSSS HELPPP!!

Answer 1

Answer:

2 m and 6.25 m for a and b respectively

Explanation:

Acceleration (a) = (2-0)/2 = 1 ms^-2 for first 2s

Distance = u*t + 0.5 *a*t^2

= 0 * 2 + 0.5 * 1 * 2^2

= 2 m

btn 2 and 4s

Acceleration a = (2.5-2)/2 = 0.25 ms^-2

Distance = u*t + 0.5 *a*t^2

=2*2+0.5 *0.25*2^2

= 4.5 m

btn 4 and 5s

Acceleration a = (1-2.5)/1 = -1.5 ms^-2

Distance = u*t + 0.5 *a*t^2

= 2.5*1 + 0.5 * -1.5*1^2

= 1.75 m

Total distance Btn 2 and 5s = 4.5 + 1.75 m

= 6.25 m